이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
using namespace std;
#include <iostream>
int B,D,N,M;
struct node1d {
int l,r,v;
node1d *c[2];
node1d(int l,int r) : l{l}, r{r} {
v = 0;
c[0] = nullptr;
c[1] = nullptr;
}
void upd(int x,int v) {
this -> v += v;
if(l != r) {
int m = (l + r) >> 1;
if(x <= m) {
if(!c[0]) c[0] = new node1d(l,m);
c[0] -> upd(x,v);
}else{
if(!c[1]) c[1] = new node1d(m + 1,r);
c[1] -> upd(x,v);
}
}
}
int qry(int x,int y) {
if(x <= l && r <= y) return v;
if(y < l || x > r) return 0;
int res = 0;
if(c[0]) res += c[0] -> qry(x,y);
if(c[1]) res += c[1] -> qry(x,y);
return res;
}
};
struct node2d {
int l,r;
node1d* v;
node2d *c[2];
node2d(int l,int r) : l{l}, r{r} {
if(B == 3) {
v = new node1d(0,160);
}else{
v = new node1d(0,160000);
}
c[0] = nullptr;
c[1] = nullptr;
}
void upd(int x,int y,int v) {
this -> v -> upd(y,v);
if(l != r) {
int m = (l + r) >> 1;
if(x <= m) {
if(!c[0]) c[0] = new node2d(l,m);
c[0] -> upd(x,y,v);
}else{
if(!c[1]) c[1] = new node2d(m + 1,r);
c[1] -> upd(x,y,v);
}
}
}
int qry(int x1,int x2,int y1,int y2) {
if(x1 <= l && r <= x2) return v -> qry(y1,y2);
if(x2 < l || x1 > r) return 0;
int res = 0;
if(c[0]) res += c[0] -> qry(x1,x2,y1,y2);
if(c[1]) res += c[1] -> qry(x1,x2,y1,y2);
return res;
}
};
int main() {
cin >> B >> N >> D >> M;
long long ans = 0;
if(B == 1) {
node1d* st = new node1d(0,75000005);
for(int i = 0;i < N;++i) {
int a;
cin >> a;
ans += st -> qry(max(0,a - D),a + D);
st -> upd(a,1);
}
}else if(B == 2) {
node2d* st = new node2d(0,160000);
for(int i = 0;i < N;++i) {
int c,d;
cin >> c >> d;
int a = (c + d);
int b = (c - d) + 80000;
ans += st -> qry(max(0,a - D),a + D,max(0,b - D),b + D);
st -> upd(a,b,1);
}
}else{
node2d* st[80];
for(int i = 0;i < 80;++i) {
st[i] = new node2d(0,160);
}
for(int i = 0;i < N;++i) {
int d,e,f;
cin >> d >> e >> f;
int a = (d + e);
int b = (d - e) + 80;
int c = f;
// cout << a << " " << b << " " << c << endl;
for(int j = 0;j < 80;++j) {
int curD = D - abs(c - j);
if(curD < 0) continue;
ans += st[j] -> qry(max(0,a - curD),a + curD,max(0,b - curD),b + curD);
}
st[c] -> upd(a,b,1);
}
}
cout << ans << endl;
return 0;
}
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