Submission #332958

#	Time	Username	Problem	Language	Result	Execution time	Memory
332958		Cantfindme	Bali Sculptures (APIO15_sculpture)	C++17	37 / 100	727 ms	620 KiB

sculpture

#include <bits/stdc++.h>
using namespace std;
#define int long long
typedef pair<int,int> pi;
#define f first
#define s second
#define FAST ios_base::sync_with_stdio(0); cin.tie(0);

const int maxb = 50;
const int maxn = 2010;
int n,A,B;
int pref[maxn];
int aa[maxn];
int dp1[110][110];
int dp2[2010];
int curbm;

int cap(int x, int groups) {
	if (dp1[x][groups] != -1) return dp1[x][groups];
	if (groups > B) return 0;
	if (x == n) {
		if (groups >= A and groups <= B) return 1;
		else return 0;
	}
	
	int res = 0;
	for (int i = x; i < n;i++) {
		int sum = pref[i] - (x == 0?0: pref[x - 1]);
		
		bool works = true;
		for (int b = 0; b < maxb and works; b++) {
			if (sum & (1 << b) and !(curbm & (1 << b))) works = false;
		}
		if (works) res = max(res, cap(i+1,groups+1));
	}
	return dp1[x][groups] = res;
}

int32_t main() {
	cin >> n >> A >> B;
	for (int i =0;i<n;i++) cin >> aa[i];
	for (int i =0;i<n;i++) {
		pref[i] = (i==0?0:pref[i-1]) + aa[i];
	}
	
	int ans = (1ll << maxb)-1;
	if (n <= 100) { //a can be > 1
		//Greedy
		for (int b = maxb-1; b >= 0; b--) {
			curbm = ans ^ (1ll << b);
			//cout << "HI: " << b << " " << curbm << "\n";
			memset(dp1,-1,sizeof dp1);
			if (cap(0,0)) ans = curbm; //If you can limit all groups to have bm that doesn't have (1<<b) then ans can also not have (1<<b)
			//cout << "NEW: " << curbm << " " << ans << "\n\n";
		}
	} else { //a can only be = 1;
		
	}
	cout << ans;
}

• Subtask 1: 0 / 9
• Subtask 2: 16 / 16
• Subtask 3: 21 / 21
• Subtask 4: 0 / 25
• Subtask 5: 0 / 29