| # | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 332074 | 2020-12-01T11:02:41 Z | alextodoran | Fishing Game (RMI19_fishing) | C++17 | 1576 ms | 107712 KB |
/**
____ ____ ____ ____ ____
||a |||t |||o |||d |||o ||
||__|||__|||__|||__|||__||
|/__\|/__\|/__\|/__\|/__\|
**/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N_MAX = 102;
const int MOD = 1e9+7;
int n, t;
int dp[3 * N_MAX][3 * N_MAX][3 * N_MAX];
bool a[3 * N_MAX], b[3 * N_MAX], c[3 * N_MAX];
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> n >> t;
dp[0][0][0] = 1;
for(int s = 1; s <= 6 * n; s++)
for(int i = 0; i <= 3 * n && i <= s; i++)
for(int j = max(0, s - 3 * n); j <= 3 * n && i + j <= s; j++)
{
int k = s - i - j;
ll sum = 0;
int start = 1;
if(min({i, j, k}) - 2 > 0)
start = 2;
for(int x = start; x <= 3; x++)
for(int y = start; y <= 3; y++)
for(int z = start; z <= 3; z++)
{
if(x != 2 && y != 2 && z != 2)
continue;
int i1 = i, j1 = j, k1 = k;
int prod = 1;
if(x == 1)
{
if(i1 + k1 > 0)
continue;
}
else if(x == 2)
{
if(i1 == 0)
continue;
prod *= i1;
i1--;
}
else
{
if(k1 == 0)
continue;
prod *= k1;
j1++;
k1--;
}
if(y == 1)
{
if(j1 + i1 > 0)
continue;
}
else if(y == 2)
{
if(j1 == 0)
continue;
prod *= j1;
j1--;
}
else
{
if(i1 == 0)
continue;
prod *= i1;
k1++;
i1--;
}
if(z == 1)
{
if(k1 + j1 > 0)
continue;
}
else if(z == 2)
{
if(k1 == 0)
continue;
prod *= k1;
k1--;
}
else
{
if(j1 == 0)
continue;
prod *= j1;
i1++;
j1--;
}
sum += 1LL * dp[i1][j1][k1] * prod;
}
dp[i][j][k] = sum % MOD;
}
while(t--)
{
for(int i = 1; i <= n * 3; i++)
a[i] = b[i] = c[i] = false;
for(int i = 1; i <= n * 2; i++)
{
int card;
cin >> card;
a[card] = true;
}
for(int i = 1; i <= n * 2; i++)
{
int card;
cin >> card;
b[card] = true;
}
for(int i = 1; i <= n * 2; i++)
{
int card;
cin >> card;
c[card] = true;
}
int I = 0, J = 0, K = 0;
for(int i = 1; i <= n * 3; i++)
I += (a[i] && b[i]);
for(int i = 1; i <= n * 3; i++)
J += (b[i] && c[i]);
for(int i = 1; i <= n * 3; i++)
K += (c[i] && a[i]);
cout << dp[I][J][K] << "\n";
}
return 0;
}
| # | Verdict | Execution time | Memory | Grader output |
|---|---|---|---|---|
| 1 | Correct | 1 ms | 364 KB | Output is correct |
| 2 | Correct | 1 ms | 492 KB | Output is correct |
| 3 | Correct | 3 ms | 1644 KB | Output is correct |
| 4 | Correct | 10 ms | 4972 KB | Output is correct |
| 5 | Correct | 138 ms | 28268 KB | Output is correct |
| 6 | Correct | 232 ms | 40300 KB | Output is correct |
| 7 | Correct | 519 ms | 54508 KB | Output is correct |
| 8 | Correct | 688 ms | 70764 KB | Output is correct |
| 9 | Correct | 1229 ms | 89396 KB | Output is correct |
| 10 | Correct | 1576 ms | 107712 KB | Output is correct |