제출 #331516

#제출 시각아이디문제언어결과실행 시간메모리
331516ignaciocantaTimovi (COCI18_timovi)C++14
20 / 80
17 ms1536 KiB
#include <bits/stdc++.h> using namespace std; using tint = long long; using ld = long double; #define forsn(i, s, n) for(int i = s; i < int(n); i++) #define forn(i, n) forsn(i, 0, n) #define trav(a, x) for(auto& a : x) using vi = vector<int>; using vl = vector<tint>; using vb = vector<bool>; #define pb push_back #define pf push_front #define rsz resize #define all(x) begin(x), end(x) #define rall(x) x.rbegin(), x.rend() #define sz(x) (int)(x).size() #define ins insert #define esta(x,c) ((c).find(x) != (c).end()) using pi = pair<int,int>; using pl = pair<tint,tint>; #define f first #define s second #define mp make_pair #define DBG(x) cerr << #x << " = " << x << endl; const int MOD = 1e9+7; const tint mod = 998244353; const int MX = 2e5+5; const tint INF = 1e18; const int inf = 2e9; const ld PI = acos(ld(-1)); const ld eps = 1e-8; const int dx[4] = {1, -1, 0, 0}; const int dy[4] = {0, 0, 1, -1}; template<class T> void remDup(vector<T> &v){ sort(all(v)); v.erase(unique(all(v)),end(v)); } bool valid(int x, int y, int n, int m){ return (0<=x && x<n && 0<=y && y<m); } int cdiv(int a, int b) { return a/b+((a^b)>0&&a%b); } //redondea p arriba int fdiv(int a, int b) { return a/b-((a^b)<0&&a%b); } //redonde p abajo void NACHO(string name = "cbarn"){ ios_base::sync_with_stdio(0); cin.tie(0); //freopen((name+".in").c_str(), "r", stdin); //freopen((name+".out").c_str(), "w", stdout); } int modd(int a, int b){ if(a % b == 0) return b; return a % b; } int main(){ NACHO(); int n, k, m; cin >> n >> k >> m; int a = cdiv(m, k); int voy; if(cdiv(a, n) % 2 == 1) voy = modd(a, n); else{ voy = n-modd(a, n); } vi ret (n); forn(i, voy-1){ ret[i] = k; m -= k; } forsn(i, voy, n){ if(m < k) ret[i] = 0; else{ ret[i] = k; m-=k; } } ret[voy-1] = m; forn(i, n) cout << ret[i] << " "; }
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