Submission #328591

#	Time	Username	Problem	Language	Result	Execution time	Memory
328591		ryansee	"The Lyuboyn" code (IZhO19_lyuboyn)	C++14	11 / 100	71 ms	7504 KiB

lyuboyn

#include "bits/stdc++.h"
using namespace std;

#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define f first
#define s second
#define cbr cerr<<"hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ll(x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x,y) (lower_bound(all(x),y)-x.begin())
#define ubd(x,y) (upper_bound(all(x),y)-x.begin())
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());    //can be used by calling rng() or shuffle(A, A+n, rng)
inline long long rand(long long x, long long y) { return rng() % (y+1-x) + x; } //inclusivesss
string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); }

using ll=long long; 
using ld=long double;
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
using pi=pair<ll,ll>; using spi=pair<ll,pi>; using dpi=pair<pi,pi>; 

long long LLINF = 1e18;
int INF = 1e9+1e6;
#define MAXN (200006)
ll n, k, t, s;
int main() {
	FAST
	cin>>n>>k>>t;
	FOR(i,1,n) {
		char ch;cin>>ch;
		s<<=1,s|=(ch&15);
	}
	function<vector<ll>(ll,ll)>dp=[&](ll n,ll k){
		assert(n>=1);
		if(k==1) {
			if(n==1) return vector<ll>{0,1};
			else {
				vector<ll> v;
				vector<ll> ret = dp(n-1, k);
				for(auto i:ret) v.eb(i<<1);
				while(ret.size()) v.eb(ret.back()<<1|1), ret.pop_back();
				return v;
			}
		}
		vector<ll> ret = dp(n-2, k-2);
		vector<ll> v;
		FOR(i,0,siz(ret)-1) if(i%2==0) v.eb(ret[i]<<2); else v.eb(ret[i]<<2|3);
		ll bit = -1;
		FOR(i,0,17) if((1<<i&ret[0]) == (1<<i&ret.back())) bit = i;
		assert(~bit);
		FOR(i,0,siz(ret)-1) if(i%2==0) v.eb(((ret[i]^(1<<bit))<<2)|1); else v.eb(((ret[i]^(1<<bit))<<2)|2);
		return v;
	};
	vector<ll> v = dp(n, k);
	ll change = 0;
	FOR(i,0,n-1) if((1<<i&v[0]) != (1<<i&s)) change|=1<<i;
	for(auto&i:v) i^=change;
	auto b=[&](ll x){
		string s;
		DEC(i,n-1,0) if(1<<i&x) s += '1'; else s += '0';
		return s;
	};
	cout<<(1<<n)<<'\n';
	for(auto i:v) cout<<b(i)<<'\n';
}

• Subtask 1: 0 / 0
• Subtask 2: 0 / 5
• Subtask 3: 0 / 3
• Subtask 4: 11 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 18
• Subtask 7: 0 / 31
• Subtask 8: 0 / 17