제출 #328450

#제출 시각아이디문제언어결과실행 시간메모리
328450ryanseeXoractive (IZhO19_xoractive)C++14
62 / 100
9 ms436 KiB
#include "interactive.h" #include "bits/stdc++.h" using namespace std; #define FAST ios_base::sync_with_stdio(false); cin.tie(0); #define pb push_back #define eb emplace_back #define ins insert #define f first #define s second #define cbr cerr<<"hi\n" #define mmst(x, v) memset((x), v, sizeof ((x))) #define siz(x) ll(x.size()) #define all(x) (x).begin(), (x).end() #define lbd(x,y) (lower_bound(all(x),y)-x.begin()) #define ubd(x,y) (upper_bound(all(x),y)-x.begin()) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //can be used by calling rng() or shuffle(A, A+n, rng) inline long long rand(long long x, long long y) { return rng() % (y+1-x) + x; } //inclusivesss string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); } using ll=int; using ld=long double; #define FOR(i,s,e) for(ll i=s;i<=ll(e);++i) #define DEC(i,s,e) for(ll i=s;i>=ll(e);--i) using pi=pair<ll,ll>; using spi=pair<ll,pi>; using dpi=pair<pi,pi>; long long LLINF = 1e18; int INF = 1e9+1e6; #define MAXN (200006) map<ll,ll> mp; vector<int> guess(int n) { vector<int> ans(n+1); ans[1]=ask(1), ans[2]=ask(2); vector<vector<ll>> v[2]; auto fix=[&](vector<ll> x,vector<ll> y){ vector<ll> z; reverse(all(x)), reverse(all(y)); while(x.size()) { if(y.empty()) { z.eb(x.back()); x.pop_back(); continue; } if(x.back()==y.back()) x.pop_back(), y.pop_back(); else z.eb(x.back()), x.pop_back(); } return z; }; FOR(i,0,6) { vector<ll> zero, one, tmp; FOR(j,3,n) { if(1<<i&j) one.eb(j); else zero.eb(j); } if(zero.size()){ tmp=get_pairwise_xor(zero); zero.eb(1); zero=get_pairwise_xor(zero); zero=fix(zero, tmp); zero.resize(unique(all(zero))-zero.begin()); if(zero[0]==0) zero.erase(zero.begin()); for(auto&i:zero) i^=ans[1]; } if(one.size()) { tmp=get_pairwise_xor(one); one.eb(2); one=get_pairwise_xor(one); one=fix(one, tmp); one.resize(unique(all(one))-one.begin()); if(one[0]==0) one.erase(one.begin()); for(auto&i:one) i^=ans[2]; } v[0].eb(zero), v[1].eb(one); } FOR(j,3,n) { mp.clear(); for(auto k:v[0]) for(auto j:k) ++ mp[j]; for(auto k:v[1]) for(auto j:k) ++ mp[j]; FOR(i,0,6) if(1<<i&j) { for(auto j:v[1][i]) -- mp[j]; } else { for(auto j:v[0][i]) -- mp[j]; } for(auto i:mp) if(i.s==0) ans[j]=i.f; } ans.erase(ans.begin()); return ans; }
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