# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
3266 |
2013-08-29T16:02:36 Z |
joonas |
쉬운 문제 (GA3_easy) |
C++ |
|
0 ms |
1088 KB |
int CountPair(int N, int *A){
int cnt=0;
for(int i=0; i < N; ++i){
for(int j=i+1; j < N; ++j) if( A[i]%A[j] == 0 ) cnt++;
}
return cnt;
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
0 ms |
1088 KB |
Output is correct |
2 |
Correct |
0 ms |
1088 KB |
Output is correct |
3 |
Correct |
0 ms |
1088 KB |
Output is correct |
4 |
Correct |
0 ms |
1088 KB |
Output is correct |
5 |
Incorrect |
0 ms |
1088 KB |
Output isn't correct |
6 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
1088 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |