| # | Time | Username | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 3266 | joonas | 쉬운 문제 (GA3_easy) | C++98 | 0 ms | 1088 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
int CountPair(int N, int *A){
int cnt=0;
for(int i=0; i < N; ++i){
for(int j=i+1; j < N; ++j) if( A[i]%A[j] == 0 ) cnt++;
}
return cnt;
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