oj.uz

Submission #321668

# Submission time Handle Problem Language Result Execution time Memory
321668 2020-11-13T03:04:38 Z daniel920712 Semiexpress (JOI17_semiexpress) C++14
18 / 100
 1 ms 384 KB 
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <vector>
#include <algorithm>
#include <set>
#include <map>

using namespace std;

long long all[3005];
map < long long , long long > Con;
set < long long > have,have2;
int main()
{
    long long N,M,K,a,b,c,x,y,z,t,ans=0,con=0,now=0,i;

    scanf("%lld %lld %lld",&N,&M,&K);
    scanf("%lld %lld %lld",&a,&b,&c);
    scanf("%lld",&t);
    for(i=0;i<M;i++)
    {
        scanf("%lld",&all[i]);
        have.insert(all[i]);
        have2.insert(all[i]);
        Con[all[i]]=(all[i]-1)*b;

    }
    con=M;
    for(i=1;i<=N;i++)
    {
        if((i-1)*a<=t)
        {
            //printf("aa %lld\n",i);
            ans++;
        }
        else
        {

            if(have.find(i)!=have.end())
            {
                if((i-1)*b<=t)
                {
                    ans++;
                }
            }
            else
            {


                if((*prev(have.lower_bound(i))-1)*b+(i-*prev(have.lower_bound(i)))*a<=t)
                {
                    //printf("cc %lld\n",i);
                    ans++;
                    continue;

                }

                if(Con[*prev(have2.lower_bound(i))]+(i-*prev(have2.lower_bound(i)))*a<=t)
                {
                    //printf("dd %lld\n",i);
                    ans++;
                    continue;

                }

                if(con==K) continue;
                if((i-*prev(have.lower_bound(i)))*c+(*prev(have.lower_bound(i))-1)*b<=t)
                {
                    //printf("bb %lld\n",i);
                    Con[i]=(i-*prev(have.lower_bound(i)))*c+(*prev(have.lower_bound(i))-1)*b;
                    ans++;
                    con++;
                    have2.insert(i);
                }


            }
        }

    }
    printf("%lld\n",ans-1);
    return 0;
}

Compilation message

semiexpress.cpp: In function 'int main()':
semiexpress.cpp:16:27: warning: unused variable 'x' [-Wunused-variable]
   16 |     long long N,M,K,a,b,c,x,y,z,t,ans=0,con=0,now=0,i;
      |                           ^
semiexpress.cpp:16:29: warning: unused variable 'y' [-Wunused-variable]
   16 |     long long N,M,K,a,b,c,x,y,z,t,ans=0,con=0,now=0,i;
      |                             ^
semiexpress.cpp:16:31: warning: unused variable 'z' [-Wunused-variable]
   16 |     long long N,M,K,a,b,c,x,y,z,t,ans=0,con=0,now=0,i;
      |                               ^
semiexpress.cpp:16:47: warning: unused variable 'now' [-Wunused-variable]
   16 |     long long N,M,K,a,b,c,x,y,z,t,ans=0,con=0,now=0,i;
      |                                               ^~~
semiexpress.cpp:18:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   18 |     scanf("%lld %lld %lld",&N,&M,&K);
      |     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~
semiexpress.cpp:19:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   19 |     scanf("%lld %lld %lld",&a,&b,&c);
      |     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~
semiexpress.cpp:20:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   20 |     scanf("%lld",&t);
      |     ~~~~~^~~~~~~~~~~
semiexpress.cpp:23:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   23 |         scanf("%lld",&all[i]);
      |         ~~~~~^~~~~~~~~~~~~~~~

Subtask #1
18.0 / 18.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Correct 1 ms 364 KB Output is correct
5 Correct 0 ms 364 KB Output is correct
6 Correct 1 ms 384 KB Output is correct
7 Correct 1 ms 364 KB Output is correct
8 Correct 1 ms 364 KB Output is correct

Subtask #2
0 / 30.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Correct 1 ms 364 KB Output is correct
5 Correct 0 ms 364 KB Output is correct
6 Correct 1 ms 384 KB Output is correct
7 Correct 1 ms 364 KB Output is correct
8 Correct 1 ms 364 KB Output is correct
9 Correct 1 ms 364 KB Output is correct
10 Correct 1 ms 364 KB Output is correct
11 Correct 1 ms 364 KB Output is correct
12 Correct 0 ms 364 KB Output is correct
13 Correct 1 ms 364 KB Output is correct
14 Correct 1 ms 364 KB Output is correct
15 Incorrect 1 ms 364 KB Output isn't correct
16 Halted 0 ms 0 KB -

Subtask #3
0 / 52.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Correct 1 ms 364 KB Output is correct
5 Correct 0 ms 364 KB Output is correct
6 Correct 1 ms 384 KB Output is correct
7 Correct 1 ms 364 KB Output is correct
8 Correct 1 ms 364 KB Output is correct
9 Correct 1 ms 364 KB Output is correct
10 Correct 1 ms 364 KB Output is correct
11 Correct 1 ms 364 KB Output is correct
12 Correct 0 ms 364 KB Output is correct
13 Correct 1 ms 364 KB Output is correct
14 Correct 1 ms 364 KB Output is correct
15 Incorrect 1 ms 364 KB Output isn't correct
16 Halted 0 ms 0 KB -