제출 #321175

#제출 시각아이디문제언어결과실행 시간메모리
321175AmineWeslatiEditor (BOI15_edi)C++14
0 / 100
1854 ms24616 KiB
//Never stop trying /*#pragma GCC target ("avx2") #pragma GCC optimize ("Ofast") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops")*/ #include "bits/stdc++.h" using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef long long ll; #define int ll typedef string str; typedef double db; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; typedef vector<str> vs; typedef vector<ld> vd; #define pb push_back #define eb emplace_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) const int MOD = 1e9 + 7; //998244353 const ll INF = 1e18; const int MX = 3e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up //constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); //mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); ll random(ll a, ll b){ return a + rng() % (b - a + 1); } #ifndef LOCAL #define cerr if(false) cerr #endif #define dbg(x) cerr << #x << " : " << x << endl; #define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; #define here() cerr << "here" << endl; void IO() { #ifdef LOCAL freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } vi adj[MX]; int N; int nb; bool vis[MX]; void dfs(int u){ vis[u]=true; nb++; for(auto v: adj[u]) if(!vis[v]) dfs(v); } vi t(4*MX,0); void update(int i, int v, int pos=1, int tl=0, int tr=N-1){ if(tl==tr){ t[pos]=v; return; } int tm=(tl+tr)/2; if(i<=tm) update(i,v,pos*2,tl,tm); else update(i,v,pos*2+1,tm+1,tr); t[pos]=max(t[pos*2],t[pos*2+1]); } int get(int l, int r, int pos=1, int tl=0, int tr=N-1){ if(l>r) return 0; if(l==tl && r==tr) return t[pos]; int mid=(tl+tr)/2; return max(get(l,min(r,mid),pos*2,tl,mid),get(max(l,mid+1),r,pos*2+1,mid+1,tr)); } int32_t main() { boost; IO(); cin>>N; vi a(N); FOR(i,0,N){ cin>>a[i]; if(a[i]>0) update(i,0); else{ a[i]=-a[i]; update(i,a[i]); } } FOR(i,0,N){ int l=i+1,r=N-1; int ans=-1; while(l<=r){ int m=(l+r)/2; if(get(i+1,m)>a[i]){ ans=m; r=m-1; } else l=m+1; } if(ans!=-1){ adj[ans].pb(i); adj[i].pb(ans); } } FOR(i,0,N-1) cout << 0 << endl; int ans=0; ROF(i,0,N) if(a[i]>0){ nb=0; dfs(i); if(nb%2==1){ans=a[i]; break;} } cout << ans << endl; return 0; } /* Careful!!! .Array bounds .Infinite loops .Uninitialized variables / empty containers .Multisets are shit Some insights: .Binary search .Graph representation .Write brute force code .Change your approach */
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...