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답안 #320074

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
320074 2020-11-07T13:09:33 Z mohamedsobhi777 Pinball (JOI14_pinball) C++14
51 / 100
 457 ms 36716 KB 
#include <bits/stdc++.h>

#pragma GCC optimize("-Ofast")
//#pragma GCC optimize("trapv")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.2,popcnt,abm,mmx,avx2,tune=native")
#pragma GCC optimize("-ffast-math")
#pragma GCC optimize("-funroll-loops")

#define I inline void
#define S struct
#define vi vector<int>
#define vii vector<pair<int, int>>
#define pii pair<int, int>
#define pll pair<ll, ll>

using namespace std;
using ll = long long;
using ld = long double;

const int N = 2e5 + 7, mod = 1e9 + 7;
const ll inf = 2e18;

// How interesting!

int n, m;
map<int, int> mp;
ll cl[N], cr[N];
vector<int> ord;

struct dev
{
        ll l, md, r, c;
        dev() {}
        dev(int _l, int _md, int _r, int _c)
        {
                l = _l;
                md = _md;
                r = _r;
                c = _c;
        }
};
vector<dev> v;

struct segtree
{
        ll tree[4 * N];
        segtree()
        {
                fill(tree, tree + 4 * N, inf);
        }
        void update(int node, int L, int R, int ix, ll val)
        {
                if (L == R)
                {
                        tree[node] = min(tree[node], val);
                        return;
                }
                int mid = (L + R) >> 1;
                if (ix <= mid)
                        update(node * 2 + 1, L, mid, ix, val);
                else
                        update(node * 2 + 2, mid + 1, R, ix, val);
                tree[node] = min(tree[node * 2 + 1], tree[node * 2 + 2]);
        }

        ll query(int node, int L, int R, int l, int r)
        {
                if (l > R || r < L)
                        return inf;
                if (L >= l && R <= r)
                        return tree[node];
                int mid = (L + R) >> 1;
                ll s1 = query(node * 2 + 1, L, mid, l, r);
                ll s2 = query(node * 2 + 2, mid + 1, R, l, r);
                return min(s1, s2);
        }
        inline ll query(int l, int r) { return query(0, 1, N, l, r); }
        inline void upd(int pos, ll val) { update(0, 1, N, pos, val); }
} s[2];

int main()
{
        ios_base::sync_with_stdio(0);
        cin.tie(0);

        //freopen("in.in", "r", stdin);
        cin >> n >> m;
        for (int i = 1; i <= n; ++i)
        {
                int a, b, c, d;
                cin >> a >> b >> c >> d;
                v.push_back(dev(a, c, b, d));
                ord.push_back(a);
                ord.push_back(b);
                ord.push_back(c);
        }
        sort(ord.begin(), ord.end());
        ord.erase(unique(ord.begin(), ord.end()), ord.end());

        for (int i = 0; i < (int)ord.size(); ++i)
        {
                mp[ord[i]] = i + 1;
        }
        for (int i = 0; i < n; ++i)
        {
                v[i].l = mp[v[i].l];
                v[i].r = mp[v[i].r];
                v[i].md = mp[v[i].md];
        }

        for (int i = 0; i < n; ++i)
        {
                cl[i] = (v[i].l == mp[1] ? 0 : s[0].query(v[i].l, v[i].r)) + v[i].c;
                cr[i] = (v[i].r == mp[m] ? 0 : s[1].query(v[i].l, v[i].r)) + v[i].c;
                s[0].upd(v[i].md, cl[i]);
                s[1].upd(v[i].md, cr[i]);
        }

        ll ans = inf;
        for (int i = 0; i < n; ++i)
        {
                ans = min(ans, cl[i] + cr[i] - v[i].c);
        }
        if (ans == inf)
                cout << -1;
        else
                cout << ans;
        return 0;
}

/*
        - bounds sir (segtree = 4N, eulerTour = 2N, ...)
        - a variable defined twice?
        - will overflow?
        - is it a good complexity?
        - don't mess up indices (0-indexed vs 1-indexed)
        - reset everything between testcases. 
*/

Subtask #1
11.0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 12908 KB Output is correct
2 Correct 7 ms 13036 KB Output is correct
3 Correct 7 ms 13036 KB Output is correct
4 Correct 7 ms 12908 KB Output is correct
5 Correct 7 ms 12908 KB Output is correct
6 Correct 7 ms 12908 KB Output is correct
7 Correct 7 ms 12908 KB Output is correct
8 Correct 7 ms 12908 KB Output is correct

Subtask #2
18.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 12908 KB Output is correct
2 Correct 7 ms 13036 KB Output is correct
3 Correct 7 ms 13036 KB Output is correct
4 Correct 7 ms 12908 KB Output is correct
5 Correct 7 ms 12908 KB Output is correct
6 Correct 7 ms 12908 KB Output is correct
7 Correct 7 ms 12908 KB Output is correct
8 Correct 7 ms 12908 KB Output is correct
9 Correct 8 ms 12908 KB Output is correct
10 Correct 8 ms 12908 KB Output is correct
11 Correct 8 ms 13036 KB Output is correct
12 Correct 8 ms 12908 KB Output is correct
13 Correct 7 ms 12908 KB Output is correct
14 Correct 7 ms 12908 KB Output is correct

Subtask #3
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 12908 KB Output is correct
2 Correct 7 ms 13036 KB Output is correct
3 Correct 7 ms 13036 KB Output is correct
4 Correct 7 ms 12908 KB Output is correct
5 Correct 7 ms 12908 KB Output is correct
6 Correct 7 ms 12908 KB Output is correct
7 Correct 7 ms 12908 KB Output is correct
8 Correct 7 ms 12908 KB Output is correct
9 Correct 8 ms 12908 KB Output is correct
10 Correct 8 ms 12908 KB Output is correct
11 Correct 8 ms 13036 KB Output is correct
12 Correct 8 ms 12908 KB Output is correct
13 Correct 7 ms 12908 KB Output is correct
14 Correct 7 ms 12908 KB Output is correct
15 Correct 7 ms 12908 KB Output is correct
16 Correct 8 ms 12908 KB Output is correct
17 Correct 9 ms 13036 KB Output is correct
18 Correct 8 ms 13036 KB Output is correct
19 Correct 9 ms 13164 KB Output is correct
20 Correct 9 ms 13036 KB Output is correct
21 Correct 8 ms 13184 KB Output is correct
22 Correct 9 ms 13164 KB Output is correct
23 Correct 9 ms 13292 KB Output is correct
24 Correct 9 ms 13164 KB Output is correct

Subtask #4
0 / 49.0

# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 12908 KB Output is correct
2 Correct 7 ms 13036 KB Output is correct
3 Correct 7 ms 13036 KB Output is correct
4 Correct 7 ms 12908 KB Output is correct
5 Correct 7 ms 12908 KB Output is correct
6 Correct 7 ms 12908 KB Output is correct
7 Correct 7 ms 12908 KB Output is correct
8 Correct 7 ms 12908 KB Output is correct
9 Correct 8 ms 12908 KB Output is correct
10 Correct 8 ms 12908 KB Output is correct
11 Correct 8 ms 13036 KB Output is correct
12 Correct 8 ms 12908 KB Output is correct
13 Correct 7 ms 12908 KB Output is correct
14 Correct 7 ms 12908 KB Output is correct
15 Correct 7 ms 12908 KB Output is correct
16 Correct 8 ms 12908 KB Output is correct
17 Correct 9 ms 13036 KB Output is correct
18 Correct 8 ms 13036 KB Output is correct
19 Correct 9 ms 13164 KB Output is correct
20 Correct 9 ms 13036 KB Output is correct
21 Correct 8 ms 13184 KB Output is correct
22 Correct 9 ms 13164 KB Output is correct
23 Correct 9 ms 13292 KB Output is correct
24 Correct 9 ms 13164 KB Output is correct
25 Correct 33 ms 14560 KB Output is correct
26 Correct 92 ms 17880 KB Output is correct
27 Correct 289 ms 24268 KB Output is correct
28 Correct 186 ms 24908 KB Output is correct
29 Correct 198 ms 22228 KB Output is correct
30 Correct 253 ms 24780 KB Output is correct
31 Correct 457 ms 30668 KB Output is correct
32 Correct 425 ms 28492 KB Output is correct
33 Correct 66 ms 17504 KB Output is correct
34 Correct 228 ms 24788 KB Output is correct
35 Incorrect 298 ms 36716 KB Output isn't correct
36 Halted 0 ms 0 KB -