제출 #319018

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
319018		caoash	K개의 묶음 (IZhO14_blocks)	C++14	53 / 100	788 ms	83016 KiB

blocks

#include <bits/stdc++.h> 
using namespace std;

using ll = long long;

using vi = vector<int>;
using vl = vector<ll>;
#define pb push_back
#define rsz resize
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()

using pi = pair<int,int>;
#define f first
#define s second
#define mp make_pair

const int MX = 100000;
const int MOD = (int) (1e9 + 7);
const int INF = 987654321;

namespace output {
  void pr(int x) {
    cout << x;
  }
  void pr(long x) {
    cout << x;
  }
  void pr(ll x) {
    cout << x;
  }
  void pr(unsigned x) {
    cout << x;
  }
  void pr(unsigned long x) {
    cout << x;
  }
  void pr(unsigned long long x) {
    cout << x;
  }
  void pr(float x) {
    cout << x;
  }
  void pr(double x) {
    cout << x;
  }
  void pr(long double x) {
    cout << x;
  }
  void pr(char x) {
    cout << x;
  }
  void pr(const char * x) {
    cout << x;
  }
  void pr(const string & x) {
    cout << x;
  }
  void pr(bool x) {
    pr(x ? "true" : "false");
  }

  template < class T1, class T2 > void pr(const pair < T1, T2 > & x);
  template < class T > void pr(const T & x);

  template < class T, class...Ts > void pr(const T & t,
    const Ts & ...ts) {
    pr(t);
    pr(ts...);
  }
  template < class T1, class T2 > void pr(const pair < T1, T2 > & x) {
    pr("{", x.f, ", ", x.s, "}");
  }
  template < class T > void pr(const T & x) {
    pr("{"); // const iterator needed for vector<bool>
    bool fst = 1;
    for (const auto & a: x) pr(!fst ? ", " : "", a), fst = 0;
    pr("}");
  }

  void ps() {
    pr("\n");
  } // print w/ spaces
  template < class T, class...Ts > void ps(const T & t,
    const Ts & ...ts) {
    pr(t);
    if (sizeof...(ts)) pr(" ");
    ps(ts...);
  }

  void pc() {
    cout << "]" << endl;
  } // debug w/ commas
  template < class T, class...Ts > void pc(const T & t,
    const Ts & ...ts) {
    pr(t);
    if (sizeof...(ts)) pr(", ");
    pc(ts...);
  }
  #define dbg(x...) pr("[", #x, "] = ["), pc(x);
}

#ifndef ONLINE_JUDGE
using namespace output;
#else
using namespace output;
#define dbg(x...)
#endif

int dp[MX][101];
int n;

struct Node {
    int val;
};

int t[4 * MX];

void upd(int p, int v) { 
  for (t[p += (n + 1)] = v; p > 1; p >>= 1) t[p >> 1] = min(t[p], t[p^1]);
}

int query(int l, int r) {
  int res = INF;
  for (l += (n + 1), r += (n + 1); l < r; l >>= 1, r >>= 1) {
    if (l&1) res = min(res, t[l++]);
    if (r&1) res = min(res, t[--r]);
  }
  return res;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    int k; cin >> n >> k;
    vi a(n + 1), lft(n + 1);
    for (int i = 1; i <= n; i++) cin >> a[i];
    stack<pi> stk;
    for (int i = 1; i <= n; i++) {
        while (!stk.empty() && stk.top().f <= a[i]) {
            stk.pop();
        }
        lft[i] = (stk.empty() ? 0 : stk.top().s);
        stk.push(mp(a[i], i));
    }
    for (int i = 0; i <= n; i++) {
        for (int j = 0; j <= k; j++) {
            dp[i][j] = INF;
        }
    }
    dp[0][0] = 0;
    for (int j = 0; j <= k; j++) {
        for (int i = 1; i <= n; i++) {
            if (lft[i] != 0) dp[i][j] = min(dp[i][j], dp[lft[i]][j]);
            if (j) {
                dp[i][j] = min(dp[i][j], query(lft[i], i) + a[i]);
            }
        }
        for (int i = 0; i <= n; i++) {
            upd(i, dp[i][j]);
        }
    }
    cout << dp[n][k] << '\n';
}

• Subtask 1: 14 / 14
• Subtask 2: 18 / 18
• Subtask 3: 21 / 21
• Subtask 4: 0 / 47