제출 #317231

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
317231		zaneyu	꿈 (IOI13_dreaming)	C++14	18 / 100	76 ms	8576 KiB

dreaming

/*input
12 8 2
0 8 4
8 2 2
2 7 4
5 11 3
5 1 7
1 3 1
1 9 5
10 6 3
*/
#include "dreaming.h"
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
 
#pragma GCC optimize("unroll-loops,no-stack-protector")
//order_of_key #of elements less than x
// find_by_order kth element
#define ll long long 
#define ld long double
#define pii pair<int,int>
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#define MP make_pair
const ll INF64=4e12;
const int INF=0x3f3f3f3f;
const ll MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-9;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
ll mult(ll a,ll b){
    return ((a%MOD)*(b%MOD))%MOD;
}
ll mypow(ll a,ll b){
    if(b<=0) return 1;
    ll res=1LL;
    while(b){
        if(b&1){
            res=(res*a)%MOD;
        }
        a=(a*a)%MOD;
        b>>=1;
    }
    return res;
}
const ll maxn=1e5+5;
const ll maxlg=__lg(maxn)+2;
vector<pii> v[maxn];
bool vis[maxn];
int bfs(int u,int dist[]){
    queue<int> q;
    q.push(u);
    dist[u]=0;
    int lst=-1;
    while(!q.empty()){
        int z=q.front();
        q.pop();
        lst=z;
        for(auto x:v[z]){
            if(dist[x.f]>dist[z]+x.s){
                dist[x.f]=dist[z]+x.s;
                q.push(x.f);
            }
        }
    }
    return lst;
}
int bfs(int u,int dist[],vector<int> &ppl){
    queue<int> q;
    q.push(u);
    dist[u]=0;
    int lst=-1;
    while(!q.empty()){
        int z=q.front();
        q.pop();
        ppl.pb(z);
        lst=z;
        for(auto x:v[z]){
            if(dist[x.f]>dist[z]+x.s){
                dist[x.f]=dist[z]+x.s;
                q.push(x.f);
            }
        }
    }
    return lst;
}
int da[maxn],db[maxn],dc[maxn];
vector<int> ppl;
int travelTime(int n, int m, int l, int A[], int B[], int T[]) {
    REP(i,m){
        v[A[i]].pb({B[i],T[i]});
        v[B[i]].pb({A[i],T[i]});
    }
    vector<int> dst;
    REP(i,n) da[i]=db[i]=dc[i]=INF,vis[i]=0;
    REP(i,n){
        if(!vis[i]){
            int u=bfs(i,dc);
            int vv=bfs(u,da);
            ppl.clear();
            bfs(vv,db,ppl);
            int mn=INF;
            for(auto x:ppl){
                vis[x]=1;
                MNTO(mn,max(da[x],db[x]));
            }
            //cout<<mn<<'\n';
            //cout<<'\n';
            dst.pb(mn);
        }
    }
    sort(ALL(dst));
    reverse(ALL(dst));
    int mx=dst[0];
    if(sz(dst)>=2) MXTO(mx,dst[0]+dst[1]+l);
    if(sz(dst)>=3) MXTO(mx,dst[1]+dst[2]+2*l);
    return mx;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 10
• Subtask 3: 0 / 23
• Subtask 4: 18 / 18
• Subtask 5: 0 / 12
• Subtask 6: 0 / 23