이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int n, k;
unordered_set<ll> dead;
ll read() {
string s; cin >> s;
ll num = 0;
for (int i = n-1; i >= 0; i--) {
if (s[n-1-i] == '1') {
num |= (1LL << i);
}
}
return num;
}
ll s[5000001];
// return true if a can reach b or if a can reach at least ct nodes
bool solve(ll a, ll b, int ct) {
unordered_set<ll> vis;
int idx = 0;
s[idx] = a;
vis.insert(a);
--ct;
while (idx >= 0) {
ll u = s[idx--];
for (int i = 0; i < n; i++) {
ll v = u ^ (1LL << i);
if (vis.count(v) || dead.count(v)) continue;
--ct;
if (ct == 0 || v == b) return true;
vis.insert(v);
s[++idx] = v;
}
}
return false;
}
int main() {
cin.tie(0)->sync_with_stdio(0);
cin >> n >> k;
ll a, b; a = read(), b = read();
if (a == b) {
cout << "TAK\n";
return 0;
}
for (int i = 0; i < k; i++) {
ll x = read();
dead.insert(x);
}
cout << (solve(a, b, n*k+1) && solve(b, a, n*k+1) ? "TAK" : "NIE") << endl;
return 0;
}
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