Submission #316528

#TimeUsernameProblemLanguageResultExecution timeMemory
316528ronnithStrah (COCI18_strah)C++14
0 / 110
1093 ms41080 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #define ll long long #define num(a) a-'0' #define charr(a) (a - 'A' + 1) #define rep(i,a,b) for(int i=a;i<b;i++) #define maxs(a,b) if(b>a)a=b #define mins(a,b) if(b<a)a=b #define bin1(a) __builtin_popcount(a) #define debug(x) cerr<<"["<<#x<<":"<<x<<"] " #define debug2(a,b) debug(a);debug(b) #define debug3(a,b,c) debug2(a,b);debug(c) #define de cerr #define gcd(a,b) __gcd(a,b) #define lcm(a,b) (((a)/(__gcd(a,b))) * b) #define print(arr) for(auto it = arr.begin();it < arr.end();it ++){cout << *it << " ";}cout << ln; #define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update> #define all(a) (a).begin(), (a).end() #define vi vector<int> #define v vector #define p pair #define pii p<int,int> #define pb push_back #define mk make_pair #define f first #define s second #define ln "\n" typedef long double ld; typedef double d; using namespace std; using namespace __gnu_pbds; ll modF=1e9+7; /*OUTPUT */ int nax = 2001; int n,m; v<v<ll>> pre(nax,v<ll>(nax,0)); v<v<char>> a(nax,v<char>(nax)); void build(){ for(int i = 1;i <= n;i ++){ for(int j = 1;j <= m;j ++){ if(a[i][j] == '#'){ pre[i][j] ++; } pre[i][j] += pre[i][j - 1]; } } for(int j = 1;j <= m;j ++){ for(int i = 1;i <= n;i ++){ pre[i][j] += pre[i - 1][j]; } } } ll sum(ll a,ll b,ll c,ll d){ ll res = pre[c][d] - pre[c][b - 1] - pre[a - 1][d] + pre[a - 1][b - 1]; return res; } void solve(){ cin >> n >> m; v<v<pii>> h(n + 1); rep(i,1,n + 1){ int lst = -1; bool fl = true; rep(j,1,m + 1){ cin >> a[i][j]; if(a[i][j] == '.'){ if(fl){ lst = j; fl = false; } } else{ if(!fl){ h[i].pb(mk(lst,j - 1)); fl = true; } } } if(!fl){ h[i].pb(mk(lst,m)); } } build(); ll ans = 0; for(ll i = 1;i <= n;i ++){ for(auto e:h[i]){ ll r = e.s; ll l = e.f; vi pr1(r - l + 2); vi pr2(r - l + 2); for(int i = 1;i < r - l + 2;i ++){ pr1[i] = i; pr1[i] += pr1[i - 1]; } for(int i = 1;i < r - l + 2;i ++){ pr2[i] = (r - l + 2 - i)* i; pr2[i] += pr2[i - 1]; } for(ll k = i;k <= n;k ++){ while(r > l and sum(i,r,k,r) != 0){ r --; } while(l < r and sum(i,l,k,l) != 0){ l ++; } if(sum(i,l,k,r) == 0){ // debug2(i,l); // debug2(k,r); // de << ln; // ans += (k - i + 1) * (r - l + 1) + ((r - l + 1) * (r - l) * (k - i + 1)) / 2; ans += (k - i + 1) * (pr2[r - l + 1] - (e.s - e.f + 1 - (r - l + 1)) * pr1[r - l + 1]); } } } } cout << ans << ln; } int main(){ ios::sync_with_stdio(0);cin.tie(0); int t = 1; // cin >> t; while(t --){ solve(); } }
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