이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")
#define endl "\n"
typedef long long ll;
template<class T, class T2> inline ostream &operator <<(ostream &out, const pair<T, T2> &x) { out << x.first << " " << x.second; return out;}
template<class T, class T2> inline istream &operator >>(istream &in, pair<T, T2> &x) { in >> x.first >> x.second; return in;}
template<class T, class T2> inline bool chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; }
template<class T, class T2> inline bool chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; }
const ll mod = 1e9 + 7;
#define out(x) "{" << (#x) << ": " << x << "} "
const ll MAX_N = 3e3 + 10;
ll cnto[MAX_N][MAX_N], cnti[MAX_N][MAX_N];
string in[MAX_N];
ll n, m;
signed main() {
ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
cin >> n >> m;
for(ll i = 0; i < n; i ++) {
cin >> in[i];
}
ll ans = 0;
for(ll i = n - 1; i >= 0; i --) {
for(ll j = m - 1; j >= 0; j --) {
cnto[i][j] = cnto[i][j + 1];
cnti[i][j] = cnti[i + 1][j];
if(in[i][j] == 'O') {
cnto[i][j] ++;
} else if(in[i][j] == 'I') {
cnti[i][j] ++;
} else {
ans += cnto[i][j] * cnti[i][j];
}
}
}
cout << ans << endl;
return 0;
}
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