Submission #315939

#	Time	Username	Problem	Language	Result	Execution time	Memory
315939		MarcoMeijer	Treatment Project (JOI20_treatment)	C++14	0 / 100	3078 ms	18508 KiB

treatment

#include <bits/stdc++.h>
using namespace std;
 
// macros
typedef __int128 ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e18
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
 
// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }
 
// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const vector<T>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class T> void OUT(const vector<T>& x) {RE(i,x.size()) OUT(i==0?"":" ",x[i]);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }
 
//===================//
//  Added libraries  //
//===================//

//===================//
//end added libraries//
//===================//
 
void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}
 
 
//===================//
//   begin program   //
//===================//
 
const int MX = 5e5;

#define X real()
#define Y imag()

typedef complex<ll> Vec;

struct LineSeg { // line seg from a -> b
    Vec a, b;
};

ll cross(Vec a, Vec b) {return a.X*b.Y - a.Y*b.X;}
bool collide(LineSeg a, LineSeg b) {
    if((cross(a.b - a.a, b.a - a.a) <= 0) != (cross(a.b - a.a, b.b - a.a) > 0) &&
       (cross(a.a - a.b, b.a - a.b) <= 0) != (cross(a.a - a.b, b.b - a.b) > 0))
        return 0;
    if((cross(b.b - b.a, a.a - b.a) <= 0) != (cross(b.b - b.a, a.b - b.a) > 0) &&
       (cross(b.a - b.b, a.a - b.b) <= 0) != (cross(b.a - b.b, a.b - b.b) > 0))
        return 0;
    return 1;
}

int n, m;
long long T[MX], L[MX], R[MX], C[MX];
vi adj[MX];
ll dist[MX];

bool isConnected(int i, int j) {
    Vec a1 = {T[i],L[i]};
    Vec a2 = {T[i],R[i]};
    Vec a3 = {T[i]+(R[i]-L[i])/2, (L[i]+R[i])/2};

    Vec b1 = {T[j],L[j]};
    Vec b2 = {T[j],R[j]};
    Vec b3 = {T[j]+(R[j]-L[j])/2, (L[j]+R[j])/2};

    LineSeg A1 = {a1,a3}, A2 = {a2, a3};
    LineSeg B1 = {b1,b3}, B2 = {b2, b3};
    if(collide(A1, B1)) return 1;
    if(collide(A1, B2)) return 1;
    if(collide(A2, B1)) return 1;
    if(collide(A2, B2)) return 1;
    return 0;
}

void program() {
    IN(n,m);
    RE(i,m) IN(T[i], L[i], R[i], C[i]);
    RE(i,m) {
        T[i]*=2;
        if(L[i] == 1) L[i] = -INF;
        else L[i] *= 2;
        if(R[i] == n) R[i] = INF;
        else R[i] = (R[i]+1)*2;
    }
    n*=2;

    RE(i,m) RE(j,m) {
        if(i == j) continue;
        if(isConnected(i,j))
            adj[i].pb(j);
    }

    priority_queue<lll,vlll,greater<lll>> pq;
    RE(i,m) dist[i] = INF;
    RE(i,m) if(L[i] == -INF) {
        dist[i] = 0;
        pq.push({0,i});
    }
    while(!pq.empty()) {
        lll p = pq.top(); pq.pop();
        if(dist[p.se] != p.fi) continue;
        FOR(v,adj[p.se]) {
            if(dist[v] > p.fi+C[p.se]) {
                dist[v] = p.fi+C[p.se];
                pq.push({dist[v], v});
            }
        }
    }

    ll ans = INF;
    RE(i,m) if(R[i] == INF) {
        ans = min(ans, dist[i]+C[i]);
    }
    if(ans == INF) ans = -1;
    OUTL((long long)ans);
}

• Subtask 1: 0 / 4
• Subtask 2: 0 / 5
• Subtask 3: 0 / 30
• Subtask 4: 0 / 61