/*
Author: Nguyen Tan Bao
Status:
Idea:
*/
#include <bits/stdc++.h>
#define FI first
#define SE second
#define EPS 1e-9
#define ALL(a) a.begin(),a.end()
#define SZ(a) int((a).size())
#define MS(s, n) memset(s, n, sizeof(s))
#define FOR(i,a,b) for (int i = (a); i <= (b); i++)
#define FORE(i,a,b) for (int i = (a); i >= (b); i--)
#define FORALL(it, a) for (__typeof((a).begin()) it = (a).begin(); it != (a).end(); it++)
//__builtin_ffs(x) return 1 + index of least significant 1-bit of x
//__builtin_clz(x) return number of leading zeros of x
//__builtin_ctz(x) return number of trailing zeros of x
using namespace std;
using ll = long long;
using ld = double;
typedef pair<int, int> II;
typedef pair<II, int> III;
typedef complex<ld> cd;
typedef vector<cd> vcd;
const ll MODBASE = 1000000007LL;
const int MAXN = 110;
const int MAXM = 1000;
const int MAXK = 16;
const int MAXQ = 200010;
const int D = 19;
int basis[D];
vector<int> a;
void insertVector(int mask) {
int originalMask = mask;
FOR(i,0,D-1) {
if (!(mask & (1<<i))) continue;
if (!basis[i]) {
basis[i] = mask;
a.push_back(originalMask);
return;
}
mask ^= basis[i];
}
}
int gray(int n) {
return n ^ (n >> 1);
}
int main() {
ios::sync_with_stdio(0);
cin.tie(nullptr);
int n, k, t;
cin >> n >> k >> t;
string s;
cin >> s;
int fi = 0;
FOR(i,0,SZ(s)-1) fi = fi * 2 + s[i] - '0';
FOR(j,1,(1<<n)-1)
if (__builtin_popcount(j) == k) insertVector(j);
if (SZ(a) < n) {
cout << "-1";
return 0;
}
cout << (1<<n) << '\n';
FOR(i,0,(1<<n)-1) {
int x = gray(i) ^ fi;
int res = 0;
FOR(j,0,n-1)
if (x & (1<<j)) res ^= a[j];
FORE(j,n-1,0) cout << (x >> j & 1);
cout << "\n";
}
return 0;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
384 KB |
Ok |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
0 ms |
384 KB |
Fail, not exactly k bits are different: line = 0 |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
392 KB |
Ok |
2 |
Correct |
1 ms |
384 KB |
Ok |
3 |
Correct |
3 ms |
384 KB |
Ok |
4 |
Correct |
1 ms |
384 KB |
Ok |
5 |
Correct |
1 ms |
384 KB |
Ok |
6 |
Correct |
1 ms |
384 KB |
Ok |
7 |
Correct |
1 ms |
384 KB |
Ok |
8 |
Correct |
2 ms |
384 KB |
Ok |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
235 ms |
5496 KB |
Ok |
2 |
Correct |
110 ms |
2680 KB |
Ok |
3 |
Correct |
1 ms |
384 KB |
Ok |
4 |
Correct |
0 ms |
384 KB |
Ok |
5 |
Correct |
1 ms |
384 KB |
Ok |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
384 KB |
Fail, not exactly k bits are different: line = 0 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
236 ms |
5496 KB |
Fail, not exactly k bits are different: line = 0 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
235 ms |
5496 KB |
Ok |
2 |
Correct |
110 ms |
2680 KB |
Ok |
3 |
Correct |
1 ms |
384 KB |
Ok |
4 |
Correct |
0 ms |
384 KB |
Ok |
5 |
Correct |
1 ms |
384 KB |
Ok |
6 |
Incorrect |
1 ms |
384 KB |
Fail, not exactly k bits are different: line = 0 |
7 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
109 ms |
2680 KB |
Fail, not exactly k bits are different: line = 0 |
2 |
Halted |
0 ms |
0 KB |
- |