# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
314923 | dolphingarlic | Longest beautiful sequence (IZhO17_subsequence) | C++14 | 8 ms | 1792 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
const int FM = (1 << 20) - 1, HM = (1 << 10) - 1;
int a[100001], k[100001];
pair<int, int> dp[1 << 10][1 << 10][11], ans[100001];
int main() {
int n;
scanf("%d", &n);
for (int i = 1; i <= n; i++) scanf("%d", a + i);
for (int i = 1; i <= n; i++) {
scanf("%d", k + i);
pair<int, int> best = {0, 0};
for (int j = 0; j < (1 << 10); j++) if (__builtin_popcount(a[i] & j) <= k[i])
best = max(best, dp[j][a[i] >> 10][k[i] - __builtin_popcount(a[i] & j)]);
best.first++;
ans[i] = best;
for (int j = 0; j < (1 << 10); j++) {
int cnt = __builtin_popcount((a[i] >> 10) & j);
dp[a[i] & HM][j][cnt] = max(dp[a[i] & HM][j][cnt], {best.first, i});
}
}
int best_idx = max_element(ans + 1, ans + n + 1) - ans;
printf("%d\n", ans[best_idx].first);
stack<int> seq;
while (best_idx) {
seq.push(best_idx);
best_idx = ans[best_idx].second;
}
while (seq.size()) {
printf("%d ", seq.top());
seq.pop();
}
}
Compilation message (stderr)
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