Submission #313957

#	Time	Username	Problem	Language	Result	Execution time	Memory
313957		nonthaphat	Counting Mushrooms (IOI20_mushrooms)	C++14	10 / 100	247 ms	760 KiB

mushrooms

#include <bits/stdc++.h>
using namespace std;
 
typedef long long ll;
typedef long double ld;
typedef double db;

typedef pair<int, int> pii;
typedef pair<int, ll> pil;
typedef pair<ll, int> pli;
typedef pair<ll, ll> pll;
typedef pair<pii, int> piipi;
typedef pair<int, pii> pipii;
typedef pair<pii, pii> piipii;
typedef pair<ll, pii> plpii;
typedef pair<db, db> pdd;
typedef pair<ld, ld> pldd;
 
typedef vector<int> vi;
typedef vector<pii> vii;
 
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define FOR2(i, a, b) for(int i=(a);i<=(b);++i)
#define ROF(i, a, b) for(int i=(b)-1;i>=(a);--i)
#define ROF2(i, a, b) for(int i=(b);i>=(a);--i)
#define GO(i, x) for(auto &i : x)
 
#define mp make_pair
#define fi first
#define se second
#define sz(x) (int)x.size()
#define all(x) (x).begin(), (x).end()
#define eb emplace_back
#define pf push_front
#define pb push_back
#define lb lower_bound
#define up upper_bound

template<typename T> inline bool min2(T &a, const T &b) { return b < a ? a = b, 1 : 0; }
template<typename T> inline bool max2(T &a, const T &b) { return a < b ? a = b, 1 : 0; }
 
const int mod = 1e9 + 7;
// const int mod = 998244353;
const int P1 = 999983, P2 = 999979;
const ld PI = acos((ld)-1);
const int dir[4][2] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
const ll INF = 1e18;
const int N = 1e6;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const int M = 100;
int use_machine(vector<int> x);
int count_mushrooms(int n){
    int count_A = 1, count_B = 0;
    vector<int> A, B;
    A.push_back(0);
    for(int i=1;i<n;i++){
        vector<int> x;
        x.push_back(0);
        x.push_back(i);
        int result = use_machine(x);
        if(result == 0){
            A.push_back(i);
            count_A++;
        }
        else{
            B.push_back(i);
            count_B++;
        }
    }
    return count_A;
}

• Subtask 1: 10 / 100