제출 #313275

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
313275		anakib1	Aliens (IOI16_aliens)	C++17	41 / 100	899 ms	119672 KiB

aliens

//나는 가상 소녀들에게 큰 호감이 있습니다.

#include <iostream>
#include <cmath>
#include <algorithm>
#include <stdio.h>
#include <cstring>
#include <string>
#include <cstdlib>
#include <vector>
#include <bitset>
#include <map>
#include <chrono>
#include <functional>
#include <unordered_set>
#include <unordered_map>
#include <numeric>
#include <queue>
#include <ctime>
#include <stack>
#include <set>
#include <list>
#include <deque>
#include <iomanip>
#include <sstream>
#include <fstream>
#include <stdarg.h>
#include <utility>

using namespace std;

#define pb push_back
#define mp make_pair
#define ll long long
#define ull unisgned long long
#define ld long double
#define all(a) a.begin(), a.end()
#define SORT(a) sort(all(a))
#define pii pair<int, int>
#define tii triple<int, int, int>
#define e 1e-7
#define PI acos(-1)
#define sz(a) (int)(a.size())
#define inf 1e17
#define vi vector<int>
#define F first
#define S second
#define rng(x) for(int _ = 0; _ < (x); _++)
#define rngi(i, x) for(int i = 0; i < (x); i++)
#define rngsi(s, i, x) for(int i = (s); i <(x); i++)
#define problem "a"

template<typename A, typename B, typename C>
struct triple {
    A X;
    B Y;
    C Z;
    triple(A a = 0, B b = 0, C c = 0) :X(a), Y(b), Z(c) {}
};
template<typename A, typename B, typename C>
triple<A, B, C> make_triple(A a = 0, B b = 0, C c = 0) {
    return triple<A, B, C>(a, b, c);
}
template<typename A, typename B, typename C>
bool operator<(const triple<A, B, C>& a, const triple<A, B, C>& b) {
    if (a.X != b.X)
        return a.X < b.X;
    if (a.Y != b.Y)
        return a.Y < b.Y;
    return a.Z < b.Z;
}
template<typename T, typename SS>
ostream& operator<<(ostream& ofs, const pair<T, SS>& p) {
    ofs << "( " << p.F << " , " << p.S << " )";
    return ofs;
}
template<typename T>
void print(T a) {
    for (auto i : a)
        cout << i << ' ';
    cout << '\n';
}
template<typename T>
T max(T a, T b, T c) {
    return max(a, max(b, c));
}
template<typename T>
T min(T a, T b, T c) {
    return min(a, min(b, c));
}
template<typename T, typename D>
D min(T a) {
    return *min_element(all(a));
}
template<typename T, typename D>
D max(T a) {
    return *max_element(all(a));
}
struct custom_hash {
    static uint64_t splitmix64(uint64_t x) {
        x += 0x9e3779b97f4a7c15;
        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
        return x ^ (x >> 31);
    }

    size_t operator()(uint64_t x) const {
        static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();
        return splitmix64(x + FIXED_RANDOM);
    }
};
ll f[4002][4002];
int d[4002][4002];
long long take_photos(int n, int m, int k, std::vector<int> r, std::vector<int> c) {
    vector<pair<ll, ll> > a;
    rngi(i, n) a.push_back({ min(r[i], c[i]), max(r[i], c[i]) });
    sort(all(a), [&](auto &x, auto &y) {return x.first < y.first || (x.first == y.first && x.second > y.second); });
    vector<pair<ll, ll> > b;
    rngi(i, n)  if (!sz(b) || b.back().second < a[i].second) b.push_back(a[i]);
    n = sz(b);
    rngi(i, n + 1) rngi(j, k + 1) f[i][j] = inf;
    rngi(i, k + 1) f[0][i] = 0;
    auto sq = [&](int x)->ll {return x * 1LL * x; };
    for(int j = 1; j <= k; j++)
        for (int i = n; i >= 1; i--) {
            int l = (j ? d[i][j - 1] : 0), u = (i < n ? d[i + 1][j] : i - 1);
            auto fx = [&](int t) -> ll{
                return f[t][j - 1] + sq(b[i - 1].second - b[t].first + 1) - sq(max(0LL, (t ? (b[t - 1].second - b[t].first + 1) : 0LL)));
            };
            int pos = l;
            for (int t = l; t <= u; t++)  if (fx(pos) >= fx(t)) pos = t;
            d[i][j] = pos;
            f[i][j] = fx(pos);
        }
    //for (int i = 1; i <= n; i++) for (int j = 1; j <= k; j++) rngi(t, i)  f[i][j] = min(f[i][j], );
    return f[n][k];
}

/*
5 7 2
0 3
4 4
4 6
4 5
4 6
*/

• Subtask 1: 4 / 4
• Subtask 2: 12 / 12
• Subtask 3: 9 / 9
• Subtask 4: 16 / 16
• Subtask 5: 0 / 19
• Subtask 6: 0 / 40