This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "horses.h"
#include <bits/stdc++.h>
#define pb push_back
#define all(x) x.begin(), x.end()
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vi = vector<int>;
using vl = vector<ll>;
using vpi = vector<pii>;
using vpl = vector<pll>;
struct Node
{
double pre, tot;
int x;
};
const int MOD = 1e9 + 7, MAXN = 5e5 + 5;
int N, X[MAXN], Y[MAXN];
double a[MAXN];
Node ST[4*MAXN];
Node operator +(const Node& _x, const Node& _y)
{
Node tmp;
tmp.pre = _x.pre;
tmp.x = _x.x;
tmp.tot = _x.tot + _y.tot;
if(_x.tot == _x.pre)
{
tmp.pre = _x.tot + _y.pre;
tmp.x = _y.x;
}
return tmp;
}
void build(int node = 0, int l = 0, int r = N - 1)
{
if(l == r)
{
ST[node] = Node{a[l], a[l], l};
return;
}
int mid = (l+r)/2, lchild = 2*node + 1, rchild = 2*node + 2;
build(lchild, l, mid);
build(rchild, mid + 1, r);
ST[node] = ST[lchild] + ST[rchild];
}
void upd(int pos, double x, int node = 0, int l = 0, int r = N - 1)
{
if(r < pos || pos < l)
return;
if(l == r)
{
a[pos] = x;
return;
}
int mid = (l+r)/2, lchild = 2*node + 1, rchild = 2*node + 2;
upd(pos, x, lchild, l, mid);
upd(pos, x, rchild, mid + 1, r);
ST[node] = ST[lchild] + ST[rchild];
}
int init(int _N, int _X[], int _Y[])
{
N = _N;
for(int i = 0; i < N; i++)
{
X[i] = _X[i];
Y[i] = _Y[i];
}
a[0] = log(X[0]) + log(Y[0]);
for(int i = 1; i < N; i++)
a[i] = log(X[i]) + log(Y[i]) - log(X[i - 1]);
build();
int idx = ST[0].x, ans = 1;
for(int i = 0; i < idx; i++)
{
ans *= X[i];
ans %= MOD;
}
ans *= Y[idx - 1];
ans %= MOD;
return ans;
}
int updateX(int pos, int val)
{
upd(pos, log(val) - log(X[pos]));
X[pos] = val;
int idx = ST[0].x, ans = 1;
for(int i = 0; i < idx; i++)
{
ans *= X[i];
ans %= MOD;
}
ans *= Y[idx - 1];
ans %= MOD;
return ans;
}
int updateY(int pos, int val)
{
upd(pos, log(val) - log(Y[pos]));
upd(pos + 1, log(Y[pos]) - log(val));
Y[pos] = val;
int idx = ST[0].x, ans = 1;
for(int i = 0; i < idx; i++)
{
ans *= X[i];
ans %= MOD;
}
ans *= Y[idx - 1];
ans %= MOD;
return ans;
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |