Submission #312591

#	Time	Username	Problem	Language	Result	Execution time	Memory
312591		aZvezda	Split the sequence (APIO14_sequence)	C++14	50 / 100	2073 ms	131076 KiB

sequence

#include <bits/stdc++.h>
using namespace std;
//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")
#define endl "\n"
typedef long long ll;
template<class T, class T2> inline ostream &operator <<(ostream &out, const pair<T, T2> &x) { out << x.first << " " << x.second; return out;}
template<class T, class T2> inline istream &operator >>(istream &in, pair<T, T2> &x) { in >> x.first >> x.second; return in;}
template<class T, class T2> inline bool chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; }
template<class T, class T2> inline bool chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; }
const ll mod = 1e9 + 7;
#define out(x) "{" << (#x) << ": " << x << "} "

const int MAX_N = 1e5 + 10, MAX_K = 210;
ll dp[MAX_N][MAX_K], hist[MAX_N][MAX_K];
ll pref[MAX_N], arr[MAX_N];

void output(int n, int k) {
    if(k == 0) {
        return;
    }
    output(hist[n][k], k - 1);
    cout << hist[n][k] << " ";
}

signed main() {
    //ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
    int n, k;
    cin >> n >> k;
    for(int i = 1; i <= n; i ++) {
        cin >> arr[i];
        pref[i] = pref[i - 1] + arr[i];
    }
    for(int i = 0; i <= n; i ++) {
        for(int j = 1; j <= k; j ++) {
            dp[i][j] = -mod;
        }
    }
    for(int i = 1; i <= n; i ++) {
        for(int j = 1; j <= k; j ++) {
            for(int q = 1; q < i; q ++) {
                if(chkmax(dp[i][j], dp[q][j - 1] + pref[q] * pref[i] - pref[q] * pref[q])) {
                    hist[i][j] = q;
                }
            }
        }
    }
    cout << dp[n][k] << endl;
    output(n, k);
    return 0;
}

/*
7 3
4 1 3 4 0 2 3
*/

• Subtask 1: 11 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 17 / 17
• Subtask 5: 0 / 21
• Subtask 6: 0 / 29