Submission #311347

#TimeUsernameProblemLanguageResultExecution timeMemory
311347eggag32Treasure (different grader from official contest) (CEOI13_treasure2)C++17
80 / 100
8 ms1792 KiB
#pragma GCC optimize ("O3") #pragma GCC target ("sse4") #include <bits/stdc++.h> #include "treasure.h" using namespace std; typedef long long ll; typedef long double ld; typedef vector<int> vi; typedef pair<int, int> pi; #define debug(x) cerr << #x << ": " << x << endl #define debug2(x, y) debug(x), debug(y) #define repn(i, a, b) for(int i = (int)(a); i < (int)(b); i++) #define rep(i, a) for(int i = 0; i < (int)(a); i++) #define all(v) v.begin(), v.end() #define mp make_pair #define pb push_back #define lb lower_bound #define ub upper_bound #define fi first #define se second #define sq(x) ((x) * (x)) const int mxN = 105; template<class T> T gcd(T a, T b){ return ((b == 0) ? a : gcd(b, a % b)); } int n, tot; int l[mxN], r[mxN], u[mxN], d[mxN]; //all of these are inclusive int LU[mxN][mxN], LD[mxN][mxN], RU[mxN][mxN], RD[mxN][mxN]; map<array<int, 4>, int> vis, ans; int qry(int r1, int c1, int r2, int c2){ array<int, 4> ar = {r1, c1, r2, c2}; if(vis[ar]) return ans[ar]; vis[ar] = 1; int ret = countTreasure(r1, c1, r2, c2); ans[ar] = ret; return ret; } int cst(int r1, int c1, int r2, int c2){ array<int, 4> ar = {r1, c1, r2, c2}; if(vis[ar]) return 0; return (r2 - r1 + 1) * (c2 - c1 + 1); } bool check(int i, int j){ int cur = 0; if(i > 1) cur += u[i - 1]; if(i < n) cur += d[i + 1]; if(j > 1) cur += l[j - 1]; if(j < n) cur += r[j + 1]; //now we do the intersections if(i > 1 && j > 1) cur -= LU[i - 1][j - 1]; if(i < n && j > 1) cur -= LD[i + 1][j - 1]; if(i > 1 && j < n) cur -= RU[i - 1][j + 1]; if(i < n && j < n) cur -= RD[i + 1][j + 1]; //assert(cur == tot || cur == (tot - 1)); return cur != tot; } void solve(int i, int j, int k){ if(k == 1){ if(~RU[i][j]) return; int q = qry(1, j, i, n); RU[i][j] = q; if(j > 1) LU[i][j - 1] = u[i] - RU[i][j]; if(i < n){ RD[i + 1][j] = r[j] - RU[i][j]; if(j > 1) LD[i + 1][j - 1] = l[j - 1] - LU[i][j - 1]; } } if(k == 2){ if(~LU[i][j]) return; int q = qry(1, 1, i, j); LU[i][j] = q; if(i < n) LD[i + 1][j] = l[j] - LU[i][j]; if(j < n){ RU[i][j + 1] = u[i] - LU[i][j]; if(i < n) RD[i + 1][j + 1] = r[j + 1] - RU[i][j + 1]; } } if(k == 3){ if(~RD[i][j]) return; int q = qry(i, j, n, n); RD[i][j] = q; if(i > 1) RU[i - 1][j] = r[j] - RD[i][j]; if(j > 1){ LD[i][j - 1] = d[i] - RD[i][j]; if(i > 1) LU[i - 1][j - 1] = l[j - 1] - LD[i][j - 1]; } } if(k == 4){ if(~LD[i][j]) return; int q = qry(i, 1, n, j); LD[i][j] = q; if(i > 1) LU[i - 1][j] = l[j] - LD[i][j]; if(j < n){ RD[i][j + 1] = d[i] - LD[i][j]; if(i > 1) RU[i - 1][j + 1] = r[j + 1] - RD[i][j + 1]; } } } int cost(int i, int j, int k){ if(k == 1) return cst(1, j, i, n); if(k == 2) return cst(1, 1, i, j); if(k == 3) return cst(i, j, n, n); if(k == 4) return cst(i, 1, n, j); } bool cmp(array<int, 4> a, array<int, 4> b){ return cost(a[1], a[2], a[3]) < cost(b[1], b[2], b[3]); } void findTreasure(int N){ n = N; memset(LD, -1, sizeof(LD)); memset(LU, -1, sizeof(LU)); memset(RD, -1, sizeof(RD)); memset(RU, -1, sizeof(RU)); tot = qry(1, 1, n, n); //l and r l[n] = r[1] = tot; repn(i, 1, n){ if(i > (n - i)) l[i] = qry(1, 1, n, i); else l[i] = tot - qry(1, i + 1, n, n); } repn(i, 2, n + 1) r[i] = tot - l[i - 1]; //u and d u[n] = d[1] = tot; repn(i, 1, n){ if(i > (n - i)) u[i] = qry(1, 1, i, n); else u[i] = tot - qry(i + 1, 1, n, n); } repn(i, 2, n + 1) d[i] = tot - u[i - 1]; //corners repn(i, 1, n + 1){ repn(j, 1, n + 1){ if(i <= (n - i)){ if(j <= (n - j)) solve(i, j, 3); else solve(i, j, 4); } else{ if(j <= (n - j)) solve(i, j, 1); else solve(i, j, 2); } } } repn(i, 1, n + 1){ repn(j, 1, n + 1){ if(RU[i][j] == -1){ vector<array<int, 4>> x; x.pb({i * (n - j + 1), i, j, 1}); if(j > 1) x.pb({i * (j - 1), i, j - 1, 2}); if(i < n) x.pb({(n - i + 2) * (n - j + 1), i + 1, j, 3}); if(i < n && j > 1) x.pb({(n - i + 2) * (j - 1), i + 1, j - 1, 4}); sort(all(x), cmp); solve(x[0][1], x[0][2], x[0][3]); } if(LU[i][j] == -1){ vector<array<int, 4>> x; if(j < n) x.pb({i * (n - j), i, j + 1, 1}); x.pb({i * j, i, j, 2}); if(i < n && j < n) x.pb({(n - i) * (n - j), i + 1, j + 1, 3}); if(i < n) x.pb({(n - i) * j, i + 1, j, 4}); sort(all(x), cmp); solve(x[0][1], x[0][2], x[0][3]); } if(RD[i][j] == -1){ vector<array<int, 4>> x; if(i > 1) x.pb({(i - 1) * (n - j + 1), i - 1, j, 1}); if(i > 1 && j > 1) x.pb({(i - 1) * (j - 1), i - 1, j - 1, 2}); x.pb({(n - i + 1) * (n - j + 1), i, j, 3}); if(j > 1) x.pb({(n - i + 1) * (j - 1), i, j - 1, 4}); sort(all(x), cmp); solve(x[0][1], x[0][2], x[0][3]); } if(LD[i][j] == -1){ vector<array<int, 4>> x; if(i > 1 && j < n) x.pb({(i - 1) * (n - j), i - 1, j + 1, 1}); if(i > 1) x.pb({(i - 1) * j, i - 1, j, 2}); if(j < n) x.pb({(n - i + 1) * (n - j), i, j + 1, 3}); x.pb({(n - i + 1) * j, i, j, 4}); sort(all(x), cmp); solve(x[0][1], x[0][2], x[0][3]); } } } repn(i, 1, n + 1){ repn(j, 1, n + 1){ if(check(i, j)) Report(i, j); } } } /* Things to look out for: - Integer overflows - Array bounds - Special cases Be careful! */

Compilation message (stderr)

treasure.cpp: In function 'int cost(int, int, int)':
treasure.cpp:109:1: warning: control reaches end of non-void function [-Wreturn-type]
  109 | }
      | ^
#Verdict Execution timeMemoryGrader output
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