이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include"horses.h"
#include<bits/stdc++.h>
//#include"grader.cpp"
using namespace std;
typedef long long int ll;
ll mod=1e9+7;
struct node{
struct temp1{
double res,x,y;
}lg;
struct temp2{
ll res,x,y;
}md;
}tree[1<<20];
void up(int v){
if(!v)return;
int x=(v<<1),y=x+1;
tree[v].lg.x=tree[x].lg.x+tree[y].lg.x,tree[v].md.x=(tree[x].md.x*tree[y].md.x)%mod;
if(tree[x].lg.res>=tree[x].lg.x+tree[y].lg.res)tree[v].lg.res=tree[x].lg.res,tree[v].md.res=tree[x].md.res;
else tree[v].lg.res=tree[x].lg.x+tree[y].lg.res,tree[v].md.res=(tree[x].md.x*tree[y].md.res)%mod;
up(v>>1);
}
void update(int v,int x,int y){
v+=(1<<19);
if(x)tree[v].md.x=x,tree[v].lg.x=log2(x);
if(y)tree[v].md.y=y,tree[v].lg.y=log2(y);
tree[v].md.res=(tree[v].md.x*tree[v].md.y)%mod,tree[v].lg.res=tree[v].lg.x+tree[v].lg.y;
up(v>>1);
}
int init(int N,int X[],int Y[]){
for(int i=0;i<N;i++)update(i,X[i],Y[i]);
return tree[1].md.res;
}
int updateX(int pos,int val){
update(pos,val,0);
return tree[1].md.res;
}
int updateY(int pos,int val){
update(pos,0,val);
return tree[1].md.res;
}
컴파일 시 표준 에러 (stderr) 메시지
horses.cpp: In function 'int init(int, int*, int*)':
horses.cpp:32:20: warning: conversion from 'll' {aka 'long long int'} to 'int' may change value [-Wconversion]
32 | return tree[1].md.res;
| ~~~~~~~~~~~^~~
horses.cpp: In function 'int updateX(int, int)':
horses.cpp:36:23: warning: conversion from 'll' {aka 'long long int'} to 'int' may change value [-Wconversion]
36 | return tree[1].md.res;
| ~~~~~~~~~~~^~~
horses.cpp: In function 'int updateY(int, int)':
horses.cpp:40:23: warning: conversion from 'll' {aka 'long long int'} to 'int' may change value [-Wconversion]
40 | return tree[1].md.res;
| ~~~~~~~~~~~^~~
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