Submission #310118

#	Time	Username	Problem	Language	Result	Execution time	Memory
310118		peti1234	Counting Mushrooms (IOI20_mushrooms)	C++17	100 / 100	9 ms	512 KiB

mushrooms

#include <bits/stdc++.h>
#include "mushrooms.h"
using namespace std;
vector<int> a, b, sz, s;
int sa, sb, pos, ert, x, adb;
bool v[20002];
void pb(int x) {
    sz.push_back(x);
}
void ap(int x) {
    a.push_back(x);
}
void bp(int x) {
    b.push_back(x);
}
void cl() {
    sz.clear();
}
void add(int a) {
    if (x%2) bp(a);
    else ap(a);
}
void fadd(int a) {
    if (x%2) ap(a);
    else bp(a);
}
int kerd() {
    return use_machine(sz);
}
void ek(int a) {
    pb(0), pb(a);
    x=kerd();
    add(a),
    cl();
}
int count_mushrooms(int n) {
    ap(0), ert=sqrt(n);
    ert=110;
    if (n<220) {
        for (int i=1; i<n; i++) ek(i);
        return a.size();
    }

    for (int i=1; i<=2; i++) ek(i);
    sa=a.size();
    if (sa>1) {
        pb(a[0]), pb(3), pb(a[1]), pb(4);
        x=kerd();
        add(4), x/=2;
        add(3);
    } else {
        pb(b[0]), pb(3), pb(b[1]), pb(4);
        x=kerd();
        fadd(4), x/=2;
        fadd(3);
    }
    pos=5;
    sa=a.size(), sb=b.size();
    while(max(sa, sb)<ert) {
        cl();
        if (sa>2) {
            pb(a[0]), pb(pos), pb(a[1]), pb(pos+1), pb(a[2]), pb(pos+2);
            x=kerd();
            add(pos+2);
            if (x<2) ap(pos), ap(pos+1), pos+=3;
            else if (x>=4) bp(pos), bp(pos+1), pos+=3;
            else {
                if (sb>1) {
                    cl();
                    pb(b[0]), pb(pos), pb(b[1]), pb(a[0]), pb(pos+1), pb(a[1]), pb(pos+3), pb(a[2]), pb(pos+4);
                    x=kerd()-1;
                    add(pos+4);
                    x/=2;
                    add(pos+3);
                    x/=2;
                    add(pos+1), fadd(pos);
                    pos+=5;
                } else {
                    cl();
                    pb(a[0]), pb(pos), pb(a[1]), pb(pos+3);
                    x=kerd();
                    add(pos+3), x/=2;
                    add(pos), fadd(pos+1);
                    pos+=4;
                }
            }
        } else {
            pb(b[0]), pb(pos), pb(b[1]), pb(pos+1), pb(b[2]), pb(pos+2);
            x=kerd();
            fadd(pos+2);
            if (x<2) bp(pos), bp(pos+1), pos+=3;
            else if (x>=4) ap(pos), ap(pos+1), pos+=3;
            else {
                if (sa>1) {
                    cl();
                    pb(a[0]), pb(pos), pb(a[1]), pb(b[0]), pb(pos+1), pb(b[1]), pb(pos+3), pb(b[2]), pb(pos+4);
                    x=kerd()-1;
                    fadd(pos+4);
                    x/=2;
                    fadd(pos+3);
                    x/=2;
                    fadd(pos+1), add(pos);
                    pos+=5;
                } else {
                    cl();
                    pb(b[0]), pb(pos), pb(b[1]), pb(pos+3);
                    x=kerd();
                    fadd(pos+3), x/=2;
                    fadd(pos), add(pos+1);
                    pos+=4;
                }
            }
        }
        sa=a.size(), sb=b.size();
    }
    while(pos<n) {
        cl();
        if (sa>=sb) {
            for (int i=0; i<sa && pos+i<n; i++) {
                pb(a[i]), pb(pos+i);
            }
            x=kerd();
            int y=sz.back();
            add(y);
            pos=1+y;
            int si=sz.size();
            adb+=((si-2)/2-x/2);

        } else {
            for (int i=0; i<sb && pos+i<n; i++) {
                pb(b[i]), pb(pos+i);
            }
            x=kerd();
            int y=sz.back();
            fadd(y);
            pos=1+y;
            adb+=(x/2);
        }
        sa=a.size(), sb=b.size();
    }
    return sa+adb;
}

• Subtask 1: 100 / 100