이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "coprobber.h"
#define DIM 510
using namespace std;
int C,R;
struct stare{
int c,r,t;
};
deque <stare> d;
int dp[DIM][DIM][2],fth[DIM][DIM];
int start (int n, bool a[MAX_N][MAX_N]){
/// stari de pierdere / de castig
/// C,R,0/1 - unde se afla politistu si hotu si cine a facut ultima miscare
/// C,C,0/1 - stare de castig
for (int i=0;i<n;i++){
dp[i][i][0] = dp[i][i][1] = 1;
d.push_back({i,i,0});
d.push_back({i,i,1});
}
while (!d.empty()){
int c = d.front().c, r = d.front().r, t = d.front().t;
d.pop_front();
if (!t){ /// trb sa mute hotu
for (int i=0;i<n;i++){
if (i == r || !a[r][i] || dp[c][i][1])
continue;
/// daca toti vecinii lui i au stare de castig atunci si asta e stare de castig
int ok = 1;
for (int j=0;j<n;j++)
if (a[i][j] && !dp[c][j][0]){
ok = 0;
break;
}
if (ok){
dp[c][i][1] = 1;
d.push_back({c,i,1});
}}
} else { /// politistul se muta sau sta pe loc
for (int i=0;i<n;i++){
if ((!a[c][i] && i != c) || dp[i][r][0])
continue;
int ok = 0;
for (int j=0;j<n;j++)
if (a[i][j] && dp[j][r][1])
ok = 1;
if (ok){
dp[i][r][0] = 1;
fth[i][r] = c; /// unde ma duc din starea asta
d.push_back({i,r,0});
}}}}
for (int i=0;i<n;i++){
int ok = 1;
for (int j=0;j<n;j++)
if (!dp[i][j][0]){
ok = 0;
break;
}
if (ok)
return i;
}
return -1;
}
int nextMove (int R){
C = fth[C][R];
return C;
}
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