제출 #309501

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
309501		caoash	사다리꼴 (balkan11_trapezoid)	C++14	26 / 100	249 ms	64264 KiB

trapezoid

#include <bits/stdc++.h> 
using namespace std;

using ll = long long;

using vi = vector<int>;
using vl = vector<ll>;
#define pb push_back
#define rsz resize
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()

using pi = pair<int,int>;
#define f first
#define s second
#define mp make_pair

const int MX = 100005;
const int MOD = (int) (1e9 + 7);
const ll INF = (ll) 1e18;

namespace output {
  void pr(int x) {
    cout << x;
  }
  void pr(long x) {
    cout << x;
  }
  void pr(ll x) {
    cout << x;
  }
  void pr(unsigned x) {
    cout << x;
  }
  void pr(unsigned long x) {
    cout << x;
  }
  void pr(unsigned long long x) {
    cout << x;
  }
  void pr(float x) {
    cout << x;
  }
  void pr(double x) {
    cout << x;
  }
  void pr(long double x) {
    cout << x;
  }
  void pr(char x) {
    cout << x;
  }
  void pr(const char * x) {
    cout << x;
  }
  void pr(const string & x) {
    cout << x;
  }
  void pr(bool x) {
    pr(x ? "true" : "false");
  }

  template < class T1, class T2 > void pr(const pair < T1, T2 > & x);
  template < class T > void pr(const T & x);

  template < class T, class...Ts > void pr(const T & t,
    const Ts & ...ts) {
    pr(t);
    pr(ts...);
  }
  template < class T1, class T2 > void pr(const pair < T1, T2 > & x) {
    pr("{", x.f, ", ", x.s, "}");
  }
  template < class T > void pr(const T & x) {
    pr("{"); // const iterator needed for vector<bool>
    bool fst = 1;
    for (const auto & a: x) pr(!fst ? ", " : "", a), fst = 0;
    pr("}");
  }

  void ps() {
    pr("\n");
  } // print w/ spaces
  template < class T, class...Ts > void ps(const T & t,
    const Ts & ...ts) {
    pr(t);
    if (sizeof...(ts)) pr(" ");
    ps(ts...);
  }

  void pc() {
    cout << "]" << endl;
  } // debug w/ commas
  template < class T, class...Ts > void pc(const T & t,
    const Ts & ...ts) {
    pr(t);
    if (sizeof...(ts)) pr(", ");
    pc(ts...);
  }
  #define dbg(x...) pr("[", #x, "] = ["), pc(x);
}

#ifdef LOCAL
using namespace output;
#endif

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;

struct chash{ 
    template <class T1, class T2> 
    size_t operator()(const pair<T1, T2>& p) const
    { 
        auto hash1 = hash<T1>{}(p.first); 
        auto hash2 = hash<T2>{}(p.second); 
        return hash1 ^ hash2; 
    } 
}; 

unordered_map<int, int> cx, cy;
map<pi, pi> st;
map<pi, int> dp;

template<int SZ> struct Seg {
    int tree[4*SZ];

    int merge(int a, int b){
        return max(a, b);
    }
    
    void update(int v, int l, int r, int i, int x) {
        if (i > r || i < l) {
            return;
        } else if (l == r) {
            tree[v] = x;
            return;
        } else {
            int m = (l + r) / 2;
            update(2 * v + 1, l, m, i, x);
            update(2 * v + 2, m + 1, r, i, x);
            tree[v] = merge(tree[2 * v + 1], tree[2 * v + 2]);
        }
    }

    int query(int v, int l, int r, int ql, int qr) {
        if (l > qr || r < ql) {
            return 0;
        } else if (l >= ql && r <= qr) {
            return tree[v];
        } else {
            int m = (l + r) / 2;
            int a = query(2 * v + 1, l, m, ql, qr);
            int b = query(2 * v + 2, m + 1, r, ql, qr);
            return merge(a, b);
        }
    }
};

Seg<MX> orz;

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    int n; cin >> n;
    vi xs, ys;
    vector<pair<pi, int>> evts;
    for (int i = 0; i < n; i++) {
        int x1, x2, y1, y2;
        cin >> x1 >> x2 >> y1 >> y2;
        pi lf = mp(x1, y1);
        pi sf = mp(x2, y2);
        st[sf] = lf;
        xs.pb(x1), ys.pb(y1);
        xs.pb(x2), ys.pb(y2);
        evts.pb(mp(lf, 0));
        evts.pb(mp(sf, 1));
    }

    sort(all(xs));
    sort(all(ys));

    int pt = 0;
    for (auto v : xs) cx[v] = pt++;
    pt = 0;
    for (auto v : ys) cy[v] = pt++;

    sort(all(evts));

    for (auto curr : evts) {
        pi rd = mp(cx[curr.f.f], cy[curr.f.s]);
        if (curr.s) {
            pi prev = st[curr.f];
            dp[rd] = dp[mp(cx[prev.f], cy[prev.s])];
            orz.update(0, 0, sz(cy), rd.s, dp[rd]);
        } else {
            dp[rd] = orz.query(0, 0, sz(cy), 0, rd.s) + 1;
        }
        // dbg(curr.f, curr.s, st[curr.f], dp[curr.f]);
    }

    int ans = orz.query(0, 0, sz(cy), 0, sz(cy));
    cout << ans << " " << 1 << '\n'; 
} 

• Subtask 1: 26 / 100