제출 #309007

#제출 시각아이디문제언어결과실행 시간메모리
309007BorisBarcaHarbingers (CEOI09_harbingers)C++14
70 / 100
185 ms31612 KiB
/* $$$$$$$\ $$\ $$$$$$$\ $$ __$$\ \__| $$ __$$\ $$ | $$ | $$$$$$\ $$$$$$\ $$\ $$$$$$$\ $$ | $$ | $$$$$$\ $$$$$$\ $$$$$$$\ $$$$$$\ $$$$$$$\ |$$ __$$\ $$ __$$\ $$ |$$ _____|$$$$$$$\ | \____$$\ $$ __$$\ $$ _____|\____$$\ $$ __$$\ $$ / $$ |$$ | \__|$$ |\$$$$$$\ $$ __$$\ $$$$$$$ |$$ | \__|$$ / $$$$$$$ | $$ | $$ |$$ | $$ |$$ | $$ | \____$$\ $$ | $$ |$$ __$$ |$$ | $$ | $$ __$$ | $$$$$$$ |\$$$$$$ |$$ | $$ |$$$$$$$ |$$$$$$$ |\$$$$$$$ |$$ | \$$$$$$$\\$$$$$$$ | \_______/ \______/ \__| \__|\_______/ \_______/ \_______|\__| \_______|\_______| */ #include <bits/stdc++.h> using namespace std; #define PB push_back #define MP make_pair #define INS insert #define LB lower_bound #define UB upper_bound #define pii pair <int,int> #define pll pair <long long, long long> #define X first #define Y second #define _ << " " << #define sz(x) (int)x.size() #define all(a) (a).begin(),(a).end() #define FOR(i, a, b) for (int i = (a); i < (b); ++i) #define FORD(i, a, b) for (int i = (a); i > (b); --i) #define FORA(i, x) for (auto &i : x) #define REP(i, n) FOR(i, 0, n) #define BITS(x) __builtin_popcount(x) #define SQ(a) (a) * (a) #define TRACE(x) cout << #x " = " << (x) << '\n'; #define YES cout << "YES\n" #define NO cout << "NO\n" #define umap unordered_map typedef long long ll; typedef long double ld; typedef vector <int> vi; typedef vector <pii> vpi; typedef vector <ll> vll; typedef vector <pll> vpl; typedef vector <double> vd; typedef vector <ld> vld; typedef vector<string> vs; //((float) t)/CLOCKS_PER_SEC const int MOD = 1e9 + 7; const double PI = acos(-1); const int INF = 1e9 + 10; const ll INFL = 1e18 + 10; const int ABC = 30; const int dx[] = {-1, 1, 0, 0}; const int dy[] = {0, 0, -1, 1}; const int dox[] = {-1, 1, 0, 0, -1, -1, 1, 1}; const int doy[] = {0, 0, -1, 1, -1, 1, -1, 1}; inline int sum(int a, int b){ if (a + b < 0) return (a + b + MOD) % MOD; return (a + b) % MOD; } inline void add(int &a, int b){ a = sum(a, b); } inline int mul(ll a, ll b){ return ((a % MOD) * ((ll)b % MOD)) % MOD; } inline int sub(int a, int b){ return (a - b + MOD) % MOD; } inline int fast_pot(ll pot, ll n){ ll ret = 1; while (n){ if (n & 1LL) ret = (ret * pot) % MOD; pot = (pot * pot) % MOD; n >>= 1LL; } return ret; } inline int divide(int a, int b){ return mul(a, fast_pot(b, MOD - 2)); } ll lcm(ll a, ll b){ return abs(a * b) / __gcd(a, b); } inline double ccw(pii A, pii B, pii C){ return (A.X * B.Y) - (A.Y * B.X) + (B.X * C.Y) - (B.Y * C.X) + (C.X * A.Y) - (C.Y * A.X); } inline int CCW(pii A, pii B, pii C){ double val = ccw(A, B, C); double eps = max(max(abs(A.X), abs(A.Y)), max(max(abs(B.X), abs(B.Y)), max(abs(C.X), abs(C.Y)))) / 1e9; if (val <= -eps) return -1; if (val >= eps) return 1; return 0; } void to_upper(string &x){ REP(i, sz(x)) x[i] = toupper(x[i]); } void to_lower(string &x){ REP(i, sz(x)) x[i] = tolower(x[i]); } string its(ll x){ if (x == 0) return "0"; string ret = ""; while (x > 0){ ret += (x % 10) + '0'; x /= 10; } reverse(all(ret)); return ret; } ll sti(string s){ ll ret = 0; REP(i, sz(s)){ ret *= 10; ret += (s[i] - '0'); } return ret; } const int N = 2e5 + 10; const int LOG = 20; struct pravac{ ll k, l; ll eval(ll x){ return k * x + l; } }; ll ccw(pravac a, pravac b, pravac c){ return a.k * (b.l - c.l) + b.k * (c.l - a.l) + c.k * (a.l - b.l); } int idx = 0; struct node{ pravac p; int anc[LOG], vel; } cht[N]; int id = 0; void Add(int par, ll k, ll l){ int curr = par; cht[id].p.k = k, cht[id].p.l = l; FORD(i, LOG - 1, -1){ if (cht[curr].anc[0] == -1 || cht[curr].vel < 2) continue; if (ccw(cht[cht[curr].anc[0]].p, cht[curr].p, cht[id].p) <= 0) curr = cht[curr].anc[0]; } cht[id].vel = cht[curr].vel + 1; REP(i, LOG){ cht[id].anc[i] = curr; if (curr != -1) curr = cht[curr].anc[i]; } //cout << "Add:" _ id _ cht[id].vel _ cht[id].anc[0] << '\n'; id++; } ll query(int node, ll x){ int curr = node; FORD(i, LOG - 1, -1){ int tmp = cht[curr].anc[i]; if (tmp == -1 || cht[tmp].anc[0] == -1) continue; if (cht[cht[tmp].anc[0]].p.eval(x) < cht[tmp].p.eval(x)) curr = cht[tmp].anc[0]; } if (cht[curr].anc[0] != -1){ if (cht[cht[curr].anc[0]].p.eval(x) < cht[curr].p.eval(x)) curr = cht[curr].anc[0]; } return cht[curr].p.eval(x); } vpl e[N]; ll n, s[N], v[N], dp[N], c_id[N]; void dfs(int cvor, int dad, ll l){ c_id[cvor] = id; if (dad){ //cout << query(c_id[cvor], -v[cvor]) << '\n'; dp[cvor] = v[cvor] * l + s[cvor] + query(c_id[dad], -v[cvor]); } Add(c_id[dad], l, dp[cvor]); //cout << cvor _ c_id[cvor] _ dp[cvor] << '\n'; FORA(nxt, e[cvor]){ if (nxt.X == dad) continue; dfs(nxt.X, cvor, l + nxt.Y); } } int main () { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); cht[0].p.k = 0, cht[0].p.l = INFL; REP(i, LOG) cht[0].anc[i] = -1; cht[0].vel = 0; id++; c_id[0] = 0; cin >> n; REP(i, n - 1){ int x, y; cin >> x >> y; ll w; cin >> w; e[x].PB({y, w}); e[y].PB({x, w}); } FOR(i, 2, n + 1) cin >> s[i] >> v[i]; dfs(1, 0, 0); FOR(i, 2, n + 1) cout << dp[i] << ' '; cout << '\n'; return 0; }
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