제출 #308560

#제출 시각아이디문제언어결과실행 시간메모리
308560aZvezdaBirthday gift (IZhO18_treearray)C++14
56 / 100
1047 ms262144 KiB
#include <bits/stdc++.h> using namespace std; //#pragma GCC optimize ("O3") //#pragma GCC target ("sse4") #define endl "\n" typedef long long ll; typedef long double ld; typedef unsigned long long ull; template<class T, class T2> inline bool chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; } template<class T, class T2> inline bool chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; } const ll mod = 1e9 + 7; template<class T> inline void fix(T &x) {if(labs(x) >= mod) {x %= mod;} if(x < 0) {x += mod;}} #define out(x) cout << __LINE__ << ": " << (#x) << " = " << (x) << endl const int MAX_N = 2e5 + 10; struct MergeSortTree { set<pair<int, int> > tree[MAX_N]; int query(int curr, int l, int r, int ql, int qr, int v) { if(ql <= l && r <= qr) { auto it = tree[curr].lower_bound({v, -1}); if(it == tree[curr].end() || (*it).first != v) { return -1; } else { return (*it).second; } } else if(l > qr || r < ql) {return -1;} int m = (l + r) / 2ll; int currAns = query(curr * 2, l, m, ql, qr, v); if(currAns != -1) {return currAns;} currAns = query(curr * 2 + 1, m + 1, r, ql, qr, v); if(currAns != -1) {return currAns;} return -1; } void change(int curr, int l, int r, int ind, int prv, int now) { if(l > ind || ind > r) {return;} auto it = tree[curr].find(pair<int, int>(prv, ind)); if(it != tree[curr].end()) {tree[curr].erase(it);} tree[curr].insert(pair<int, int>(now, ind)); if(l == r) {return;} int m = (l + r) / 2ll; change(curr * 2, l, m, ind, prv, now); change(curr * 2 + 1, m + 1, r, ind, prv, now); } void print(int curr, int l, int r) { return; cout << curr << " " << l << " " << r << ": "; for(auto it : tree[curr]) {cout << "{" << it.first << ", " << it.second << "} ";} cout << endl; if(l == r) {return;} int m = (l + r) / 2ll; print(curr * 2, l, m); print(curr * 2 + 1, m + 1, r); } }; MergeSortTree diff, seq; const int LOG = 20; int par[MAX_N][LOG], d[MAX_N]; vector<int> g[MAX_N]; void dfs(int x, int p) { par[x][0] = p; d[x] = d[p] + 1; for(int i = 1; i < LOG; i ++) { par[x][i] = par[par[x][i - 1]][i - 1]; } for(auto it : g[x]) { if(it == p) {continue;} dfs(it, x); } } int lca(int a, int b) { if(d[a] < d[b]) {swap(a, b);} for(int i = LOG - 1; i >= 0; i --) { if(d[par[a][i]] >= d[b]) { a = par[a][i]; } } if(a == b) {return a;} for(int i = LOG - 1; i >= 0; i --) { if(par[a][i] != par[b][i]) { a = par[a][i]; b = par[b][i]; } } return par[a][0]; } int n, m, q; int arr[MAX_N]; signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cin >> n >> m >> q; for(int i = 0; i < n - 1; i ++) { int a, b; cin >> a >> b; g[a].push_back(b); g[b].push_back(a); } dfs(1, 0); for(int i = 1; i <= m; i ++) { cin >> arr[i]; seq.change(1, 1, m, i, 0, arr[i]); } for(int i = 1; i <= m - 1; i ++) { int curr = lca(arr[i], arr[i + 1]); diff.change(1, 1, m, i, 0, curr); } while(q --) { int t; cin >> t; if(t == 1) { int a, v; cin >> a >> v; seq.change(1, 1, m, a, arr[a], v); diff.print(1, 1, m); if(a != m) { diff.change(1, 1, m, a, lca(arr[a], arr[a + 1]), lca(v, arr[a + 1])); } diff.print(1, 1, m); if(a != 1) { diff.change(1, 1, m, a - 1, lca(arr[a], arr[a - 1]), lca(v, arr[a - 1])); } arr[a] = v; diff.print(1, 1, m); } else { int l, r, v; cin >> l >> r >> v; int ans = seq.query(1, 1, m, l, r, v); if(ans != -1) { cout << ans << " " << ans << endl; continue; } ans = diff.query(1, 1, m, l, r - 1, v); if(ans != -1) { cout << ans << " " << ans + 1 << endl; continue; } cout << -1 << " " << -1 << endl; } } return 0; } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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