제출 #308071

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
308071		jwvg0425	카니발 티켓 (IOI20_tickets)	C++17	100 / 100	1069 ms	95728 KiB

tickets

#include "tickets.h"
#include <stdio.h>
#include <vector>
#include <queue>
#include <algorithm>
#include <iostream>
#include <string>
#include <bitset>
#include <map>
#include <set>
#include <tuple>
#include <string.h>
#include <math.h>
#include <random>
#include <functional>
#include <assert.h>
#include <math.h>
#define all(x) (x).begin(), (x).end()
#define xx first
#define yy second

using namespace std;

template<typename T, typename Pr = less<T>>
using pq = priority_queue<T, vector<T>, Pr>;
using i64 = long long int;
using ii = pair<int, int>;
using ii64 = pair<i64, i64>;

vector<ii64> ts[1505];
ii trace[1505];

i64 find_maximum(int k, vector<vector<int>> x)
{
    int n = x.size();
    int m = x[0].size();

    for (int i = 0; i < n; i++)
        for (int j = 0; j < m; j++)
            ts[i].emplace_back(x[i][j], j);

    vector<vector<int>> ans(n, vector<int>(m, -1));

    i64 ret = 0;
    pq<ii64, greater<ii64>> q;

    for (int color = 0; color < n; color++)
    {
        sort(all(ts[color]));

        for (int i = m - 1; i >= m - k; i--)
            ret += ts[color][i].xx;

        trace[color] = ii(0, k);
        q.emplace(ts[color][m - k].xx + ts[color][0].xx, color);
    }

    for (int i = 0; i < k * n / 2; i++)
    {
        auto [val, c] = q.top();
        q.pop();
        ret -= val;
        trace[c].xx++;
        trace[c].yy--;

        if (trace[c].xx < k)
            q.emplace(ts[c][trace[c].xx].xx + ts[c][m - trace[c].yy].xx, c);
    }

    int gidx = 0;
    for (int color = 0; color < n; color++)
    {
        for (int i = 0; i < trace[color].xx; i++)
        {
            ans[color][ts[color][i].yy] = gidx;
            gidx = (gidx + 1) % k;
        }

        int lgi = gidx;

        for (int i = 0; i < trace[color].yy; i++)
        {
            ans[color][ts[color][m - 1 - i].yy] = lgi;
            lgi = (lgi + 1) % k;
        }
    }

    allocate_tickets(ans);

    return ret;
}

• Subtask 1: 11 / 11
• Subtask 2: 16 / 16
• Subtask 3: 14 / 14
• Subtask 4: 14 / 14
• Subtask 5: 12 / 12
• Subtask 6: 23 / 23
• Subtask 7: 10 / 10