제출 #306956

#제출 시각아이디문제언어결과실행 시간메모리
306956HynDufMergers (JOI19_mergers)C++11
100 / 100
840 ms87724 KiB
#include <bits/stdc++.h> #define task "M" #define all(v) (v).begin(), (v).end() #define rep(i, l, r) for (int i = (l); i <= (r); ++i) #define Rep(i, r, l) for (int i = (r); i >= (l); --i) #define DB(X) { cerr << #X << " = " << (X) << '\n'; } #define DB1(A, _) { cerr << #A << "[" << _ << "] = " << (A[_]) << '\n'; } #define DB2(A, _, __) { cerr << #A << "[" << _ << "][" << __ << "] = " << (A[_][__]) << '\n'; } #define DB3(A, _, __, ___) { cerr << #A << "[" << _ << "][" << __ << "][" << ___ << "] = " << (A[_][__][___]) << '\n'; } #define PR(A, l, r) { cerr << '\n'; rep(_, l, r) DB1(A, _); cerr << '\n';} #define SZ(x) ((int)(x).size()) #define pb push_back #define eb emplace_back #define pf push_front #define F first #define S second #define by(x) [](const auto& a, const auto& b) { return a.x < b.x; } // sort(arr, arr + N, by(a)); #define next ___next #define prev ___prev #define y1 ___y1 #define left ___left #define right ___right #define y0 ___y0 #define div ___div #define j0 ___j0 #define jn ___jn using ll = long long; using ld = long double; using ull = unsigned long long; using namespace std; typedef pair<int, int> ii; typedef pair<ii, int> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<ll> vl; const int N = 5e5 + 2; int n, numCol, deg[N], rt[N], dep[N], par[N]; vi col[N], g[N]; void dfs(int u) { dep[u] = dep[par[u]] + 1; for (int v : g[u]) if (v != par[u]) { par[v] = u; dfs(v); } } int frt(int i) {return rt[i] == i ? i : rt[i] = frt(rt[i]);} bool in[N]; int main() { #ifdef HynDuf freopen(task".in", "r", stdin); //freopen(task".out", "w", stdout); #else ios_base::sync_with_stdio(false); cin.tie(nullptr); #endif cin >> n >> numCol; rep(I, 2, n) { int u, v; cin >> u >> v; g[u].eb(v); g[v].eb(u); } dfs(1); rep(i, 1, n) { int c; cin >> c; col[c].eb(i); rt[i] = i; } rep(c, 1, numCol) { rep(i, 1, SZ(col[c]) - 1) { int u = frt(col[c][i - 1]), v = frt(col[c][i]); while (u != v) { if (dep[u] < dep[v]) swap(u, v); rt[u] = frt(par[u]); u = rt[u]; } } } vi change; rep(i, 1, n) { for (int v : g[i]) if (frt(v) != frt(i) && !in[frt(v)]) change.eb(frt(v)), in[frt(v)] = 1, deg[frt(v)]++; for (int v : change) in[v] = 0; change.clear(); } int cnt = 0; rep(i, 1, n) cnt += (deg[i] == 1); cout << (cnt + 1) / 2; return 0; }
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