제출 #306783

#제출 시각아이디문제언어결과실행 시간메모리
306783syyJakarta Skyscrapers (APIO15_skyscraper)C++17
100 / 100
269 ms23928 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; #define FOR(i, a, b) for(int i = (int)a; i <= (int)b; i++) #define DEC(i, a, b) for(int i = (int)a; i >= (int)b; i--) typedef pair<int, int> pi; typedef pair<int, pi> pii; typedef pair<pi, pi> pipi; #define f first #define s second typedef vector<int> vi; typedef vector<pi> vpi; typedef vector<pii> vpii; #define pb push_back #define pf push_front #define all(v) v.begin(), v.end() #define disc(v) sort(all(v)); v.resize(unique(all(v)) - v.begin()); #define INF (int) 1e9 + 100 #define LLINF (ll) 1e18 #define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //can be used by calling rng() or shuffle(A, A+n, rng) inline ll rand(ll x, ll y) { ++y; return (rng() % (y-x)) + x; } //inclusivesss const int sqr = 175; int n, m, b[30005], p[30005], dist[30005][175]; vi big[30005], small[30005]; deque<pii> dq; //building, cur jump, dist int main() { fastio; cin >> n >> m; FOR(i, 0, m-1) { cin >> b[i] >> p[i]; if (p[i] > sqr) big[b[i]].pb(p[i]); else small[b[i]].pb(p[i]); } memset(dist, -1, sizeof dist); dist[b[0]][0] = 0; dq.push_back(pii(0, pi(b[0], 0))); while (!dq.empty()) { pii cur = dq.front(); dq.pop_front(); int x = cur.s.f, d = cur.f, jump = cur.s.s; if (jump == 0) { //transferring if (d != dist[x][0]) continue; for (auto it:big[x]) { if (x + it < n) dq.push_back(pii(d+1, pi(x+it, it))); if (x - it >= 0) dq.push_back(pii(d+1, pi(x-it, -it))); } for (auto it:small[x]) { if (dist[x][it] == -1 or dist[x][it] > d) { dist[x][it] = d; dq.push_front(pii(d, pi(x, it))); } } } else if (jump > 0 and jump < sqr) { //small dog if (d != dist[x][jump]) continue; if (dist[x][0] == -1 or dist[x][0] > d) { dist[x][0] = d; dq.push_front(pii(d, pi(x, 0))); } for (auto it:{x - jump, x + jump}) if (it >= 0 and it < n) { if (dist[it][jump] == -1 or dist[it][jump] > d + 1) { dist[it][jump] = d + 1; dq.push_back(pii(d+1, pi(it, jump))); } } } else { //big dog //get off if (dist[x][0] == -1 or dist[x][0] > d) { dist[x][0] = d; dq.push_front(pii(d, pi(x, 0))); } //continue if (x + jump < n and x + jump >= 0) dq.push_back(pii(d+1, pi(x+jump, jump))); } } cout << dist[b[1]][0]; }
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