이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "supertrees.h"
#include <bits/stdc++.h>
using namespace std;
const int MXN = 1005;
vector<int> par_line(MXN, 0), par_comp(MXN, 0), line[MXN], cycle_vertex[MXN];
vector<bool> check(MXN, false);
std::vector<std::vector<int>> answer;
int temp[MXN][MXN], n;
int root(int i, vector<int> &par) {
while(i != par[par[i]]) {
par[i] = par[par[i]];
i = par[par[i]];
}
return i;
}
void mergeset(int a, int b, vector<int> &par) {
par[root(a, par)] = root(b, par);
}
void dfs(int u, int b, int prev) {
for(int i = 0; i < n; i++) {
if(i == u || i == prev || i == b) {
continue;
}
if(answer[u][i]) {
if(!check[i]) {
check[i] = true;
temp[b][i]++;
dfs(i, b, u);
check[i] = false;
}
}
}
}
int construct(std::vector<std::vector<int>> p) {
n = p.size();
for (int i = 0; i < n; i++) {
std::vector<int> row;
row.resize(n);
answer.push_back(row);
par_line[i] = i;
par_comp[i] = i;
}
for(int i = 0; i < n; i++) {
bool cycle_data = false, found_comp = false;
for(int j = 0; j < n; j++) {
if(i == j) continue;
if(p[i][j] != 0) {
found_comp = true;
if(p[i][j] == 2) {
cycle_data = true;
if(root(i, par_comp) != root(j, par_comp)) {
mergeset(i, j, par_comp);
}
continue;
}
if(root(i, par_line) != root(j, par_line)) {
mergeset(i, j, par_line);
}
}
}
if(!cycle_data) {
par_comp[i] = -1;
}
if(!found_comp) {
par_line[i] = -1;
}
}
for(int i = 0; i < n; i++) {
if(par_line[i] != -1) {
line[root(i, par_line)].push_back(i);
}
}
for(int i = 0; i < n; i++) {
int sz = line[i].size();
if(sz) {
if(par_comp[line[i][0]] != -1){
cycle_vertex[root(line[i][0], par_comp)].push_back(line[i][0]);
}
}
for(int j = 0; j < sz - 1; j++) {
int x = line[i][j], y = line[i][j + 1];
answer[x][y] = answer[y][x] = 1;
}
}
for(int i = 0; i < n; i++) {
int sz = cycle_vertex[i].size();
if(sz >= 3) {
cycle_vertex[i].push_back(cycle_vertex[i][0]);
for(int j = 0; j < sz; j++) {
int x = cycle_vertex[i][j], y = cycle_vertex[i][j + 1];
answer[x][y] = answer[y][x] = 1;
}
} else if(sz > 0) {
return 0;
}
}
for(int i = 0; i < n; i++) {
dfs(i, i, -1);
temp[i][i] = 1;
}
for(int i = 0; i < n; i++) {
for(int j = 0; j < n; j++) {
// printf("%d ", temp[i][j]);
if(temp[i][j] != p[i][j]) {
return 0;
}
}
}
build(answer);
return 1;
}
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