이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "supertrees.h"
#include <vector>
using namespace std;
const int NMAX = 1e3 + 1;
int N;
int roads[NMAX][NMAX];
vector < int > tree[NMAX], cycle[NMAX];
bool Edge[NMAX][NMAX];
vector < vector < int > > ans;
int Id_tree[NMAX];
static inline void Add_Edge (int X, int Y)
{
Edge[X][Y] = Edge[Y][X] = 1;
return;
}
static inline void DFS (int Node, int Father, int Id)
{
Id_tree[Id] = Id;
for(auto it : tree[Node])
if(it != Father)
Add_Edge(Node, it), DFS(it, Node, Id);
return;
}
static inline void Build_trees ()
{
for(int i = 1; i <= N; ++i)
if(!tree[i].empty())
DFS(i, -1, i);
return;
}
static inline void Solve ()
{
Build_trees();
return;
}
static inline void Reconstruct ()
{
for(int i = 1; i <= N; ++i)
{
vector < int > line;
for(int j = 1; j <= N; ++j)
line.push_back(Edge[i][j]);
ans.push_back(line);
}
return;
}
int construct (vector < vector < int > > p)
{
N = (int)p.size();
for(int i = 0; i < N; ++i)
for(int j = 0; j < N; ++j)
{
roads[i + 1][j + 1] = p[i][j];
if(p[i][j] == 1)
tree[i + 1].push_back(j + 1);
else if(p[i][j] == 2)
cycle[i + 1].push_back(j + 1);
else if(p[i][j] == 3)
return 0;
}
Solve();
build(ans);
return 1;
}
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