제출 #305683

#제출 시각아이디문제언어결과실행 시간메모리
305683ntfx시간이 돈 (balkan11_timeismoney)C++17
100 / 100
855 ms632 KiB
/* Problem: https://oj.uz/problem/view/balkan11_timeismoney Solution: http://www.boi2011.ro/resurse/tasks/timeismoney-sol.pdf */ #include <bits/stdc++.h> using namespace std; #ifdef LOCAL #define D(a) cerr << #a << " = " << a << endl #else #define D(a) 8 #endif #define fastio ios_base::sync_with_stdio(0); cin.tie(0) #define dforsn(i,s,n) for(int i=int(n-1);i>=int(s);i--) #define forsn(i,s,n) for(int i=int(s);i<int(n);i++) #define all(a) (a).begin(),(a).end() #define dforn(i,n) dforsn(i,0,n) #define forn(i,n) forsn(i,0,n) #define si(a) int((a).size()) #define pb emplace_back #define mp make_pair #define snd second #define fst first #define endl '\n' using pii = pair<int,int>; using vi = vector<int>; using ll = long long; struct DSU { vi par; DSU(int n): par(n) { iota(all(par), 0); } int find(int u) { return par[u] == u ? u : par[u] = find(par[u]); } bool join(int u, int v) { if ((u = find(u)) == (v = find(v))) return false; return par[v] = u, true; } }; const int N = 200, M = 1e4; int n, m, A, B, sumT, sumC; int t[M], c[M], mst[N]; int src[M], dst[M]; ll mn = 1e18; pii ids[M]; struct Point { int x, y; bool collinear(const Point &p1, const Point &p2) { return ll(p2.y - p1.y) * (x - p1.x) == ll(y - p1.y) * (p2.x - p1.x); } }; // Minimize a * sumT + b * sumC = v Point optimize(int a, int b) { forn(i, m) ids[i] = {a*t[i] + b*c[i], i}; sort(ids, ids + m); sumT = 0, sumC = 0; int pos = 0; DSU dsu(n); forn(i, m) { int id = ids[i].snd; if (dsu.join(src[id], dst[id])) sumT += t[id], sumC += c[id], mst[pos++] = id; } ll v = ll(sumT) * sumC; if (v < mn) mn = v, A = a, B = b; return {sumC, sumT}; } void computeConvexHull(const Point &p1, const Point &p2) { Point p = optimize(p2.x - p1.x, p1.y - p2.y); if (p.collinear(p1, p2)) return; computeConvexHull(p1, p), computeConvexHull(p, p2); } int main() { fastio; cin >> n >> m; forn(i, m) cin >> src[i] >> dst[i] >> t[i] >> c[i]; computeConvexHull(optimize(0, 1), optimize(1, 0)); optimize(A, B); cout << sumT << ' ' << sumC << endl; forn(i, n-1) cout << src[mst[i]] << ' ' << dst[mst[i]] << endl; return 0; }
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