이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "koala.h"
#include <bits/stdc++.h>
using namespace std;
int arr1[100], arr2[100];
vector<int> ord;
set<int> used;
int n, w;
int minValue(int N, int W) {
// TODO: Implement Subtask 1 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
for(int i = 0; i < N; ++i){
arr1[i] = 0;
}
arr1[0] = 1;
playRound(arr1, arr2);
for(int i = 0; i < N; ++i){
if(arr2[i] <= arr1[i])return i;
}
return 0;
}
int maxValue(int N, int W) {
// TODO: Implement Subtask 2 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
vector<int> go(N);
iota(go.begin(),go.end(),0);
int sz = go.size();
while(sz != 1){
for(int i = 0; i < N; ++i){
arr1[i] = 0;
arr2[i] = 0;
}
for(int i = 0; i < sz; ++i){
arr1[go[i]] = W/sz;
}
playRound(arr1,arr2);
go.clear();
for(int i = 0; i < N; ++i){
if(arr2[i] > arr1[i] && arr1[i] > 0)go.push_back(i);
}
sz = go.size();
}
return go[0];
}
int greaterValue(int N, int W) {
// TODO: Implement Subtask 3 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
memset(arr1,0,N);
arr1[0] = 4;
arr1[1] = 4;
playRound(arr1,arr2);
if(arr2[0] <= 4 && arr2[1] <= 4){
arr1[0] = 2;
arr1[1] = 2;
playRound(arr1,arr2);
if(arr2[0] <= 2 && arr2[1] <= 2){
arr1[0] = 1;
arr1[1] = 1;
playRound(arr1,arr2);
return arr2[1] > arr2[0];
}
if(arr2[0] > 2 && arr2[1] > 2){
arr1[0] = 3;
arr1[1] = 3;
playRound(arr1,arr2);
return arr2[1] > arr2[0];
}
return arr2[1] > arr2[0];
}
if(arr2[0] > 4 && arr2[1] > 4){
arr1[0] = 8;
arr1[1] = 8;
playRound(arr1,arr2);
if(arr2[0] <= 8 && arr2[1] <= 8){
arr1[0] = 6;
arr1[1] = 6;
playRound(arr1,arr2);
return arr2[1] > arr2[0];
}
return arr2[1] > arr2[0];
}
return arr2[1] > arr2[0];
}
bool comp(int a, int b){
for(int i = 0; i < n; ++i){
arr1[i] = 0;
}
arr1[a] = arr1[b] = n;
playRound(arr1,arr2);
return arr2[a] < arr2[b];
}
void allValues(int N, int W, int *P) {
n = N;w = W;
if(N*2 == W){
// TODO: Implement Subtask 4 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
vector<int> x(N);
iota(x.begin(),x.end(),0);
stable_sort(x.begin(),x.end(),comp);
for(int i = 0; i < N; ++i){
P[x[i]] = i+1;
}
}
else {
}
// TODO: Implement Subtask 5 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
}
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