제출 #304571

#제출 시각아이디문제언어결과실행 시간메모리
304571HynDuf케이크 (CEOI14_cake)C++11
83.33 / 100
2080 ms5600 KiB
#include <bits/stdc++.h>

#define task "C"
#define all(v) (v).begin(), (v).end()
#define rep(i, l, r) for (int i = (l); i <= (r); ++i)
#define Rep(i, r, l) for (int i = (r); i >= (l); --i)
#define DB(X) { cerr << #X << " = " << (X) << '\n'; }
#define DB1(A, _) { cerr << #A << "[" << _ << "] = " << (A[_]) << '\n'; }
#define DB2(A, _, __) { cerr << #A << "[" << _ << "][" << __ << "] = " << (A[_][__]) << '\n'; }
#define DB3(A, _, __, ___) { cerr << #A << "[" << _ << "][" << __ << "][" << ___ << "] = " << (A[_][__][___]) << '\n'; }
#define PR(A, l, r) { cerr << '\n'; rep(_, l, r) DB1(A, _); cerr << '\n';}
#define SZ(x) ((int)(x).size())
#define pb push_back
#define eb emplace_back
#define pf push_front
#define F first
#define S second
#define by(x) [](const auto& a, const auto& b) { return a.x < b.x; } // sort(arr, arr + N, by(a));
#define next ___next
#define prev ___prev
#define y1 ___y1
#define left ___left
#define right ___right
#define y0 ___y0
#define div ___div
#define j0 ___j0
#define jn ___jn

using ll = long long;
using ld = long double;
using ull = unsigned long long;
using namespace std;
typedef pair<int, int> ii;
typedef pair<ii, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<ll> vl;
const int N = 250002;
int read(){int s=0,f=1;char ch=getchar();while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}while(ch>='0'&&ch<='9'){s=(s<<3)+(s<<1)+ch-'0',ch=getchar();}return s*f;}
char readch() {char c; do c = getchar(); while (c == '\n' || c == ' '); return c;}
template <typename T> inline void wrip(T x) {if (x > 9) wrip(x / 10); putchar(x%10 + 48); }
template <typename T> inline void writeln(T x) {if (x < 0) putchar('-'), x = -x; wrip(x); putchar('\n');}
int n, A, q, a[N];
set<ii> mxa;
int it[4 * N];
void build(int id, int l, int r)
{
    if (l == r)
    {
        it[id] = a[l];
        return;
    }
    int m = (l + r) >> 1;
    build(id << 1, l, m);
    build((id << 1) | 1, m + 1, r);
    it[id] = max(it[id << 1], it[(id << 1) | 1]);
}
void update(int id, int l, int r, int p)
{
    if (l > p || r < p) return;
    if (l == r)
    {
        it[id] = a[p];
        return;
    }
    int m = (l + r) >> 1;
    update(id << 1, l, m, p);
    update((id << 1) | 1, m + 1, r, p);
    it[id] = max(it[id << 1], it[(id << 1) | 1]);
}
int query(int id, int l, int r, int L, int R)
{
    if (l > R || r < L) return -1e9;
    if (L <= l && r <= R) return it[id];
    int m = (l + r) >> 1;
    return max(query(id << 1, l, m, L, R), query((id << 1) | 1, m + 1, r, L, R));
}
int main()
{
#ifdef HynDuf
    freopen(task".in", "r", stdin);
    //freopen(task".out", "w", stdout);
#else
    ios_base::sync_with_stdio(false); cin.tie(nullptr);
#endif
    //cin >> n >> A;
    n = read(), A = read();
    rep(i, 1, n)
    {
        a[i] = read();
        mxa.insert({a[i], i});
        if (SZ(mxa) > 10) mxa.erase(mxa.begin());
    }
    build(1, 1, n);
    q = read();
    while (q--)
    {
        char t;
        int x;
        t = readch();
        x = read();
        if (t == 'E')
        {
            int r;
            r = read();
            vii change;
            rep(i, 1, r - 1)
            {
                auto it = mxa.end(); it--;
                if (it->S != x)
                {
                    change.pb({it->F + 1, it->S});
                    a[it->S]++;
                    update(1, 1, n, it->S);
                } else i--;
                mxa.erase(it);
            }
            auto it = mxa.lower_bound({a[x], 0});
            if (it != mxa.end() && it->F == a[x]) mxa.erase(it);
            a[x] = (change.empty() ? (mxa.rbegin()->F + 1) : (change.back().F - 1));
            change.pb({a[x], x});
            update(1, 1, n, x);

            for (ii v : change) mxa.insert(v);
            if (SZ(mxa) > 10) mxa.erase(mxa.begin());

        } else if (x > A)
        {
            int mx = query(1, 1, n, A + 1, x);
            int l = 1, r = A - 1;
            while (l <= r)
            {
                int m = (l + r) >> 1;
                if (query(1, 1, n, m, A - 1) > mx) l = m + 1;
                else r = m - 1;
            }
            writeln(x - l);
        } else if (x < A)
        {
            int mx = query(1, 1, n, x, A - 1);
            int l = A + 1, r = n;
            while (l <= r)
            {
                int m = (l + r) >> 1;
                if (query(1, 1, n, A + 1, m) > mx) r = m - 1;
                else l = m + 1;
            }
            writeln(r - x);
        } else puts("0");
    }
    return 0;
}
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