Submission #303932

#TimeUsernameProblemLanguageResultExecution timeMemory
303932BorisBarcaHarbingers (CEOI09_harbingers)C++14
0 / 100
632 ms65540 KiB
/* $$$$$$$\ $$\ $$$$$$$\ $$ __$$\ \__| $$ __$$\ $$ | $$ | $$$$$$\ $$$$$$\ $$\ $$$$$$$\ $$ | $$ | $$$$$$\ $$$$$$\ $$$$$$$\ $$$$$$\ $$$$$$$\ |$$ __$$\ $$ __$$\ $$ |$$ _____|$$$$$$$\ | \____$$\ $$ __$$\ $$ _____|\____$$\ $$ __$$\ $$ / $$ |$$ | \__|$$ |\$$$$$$\ $$ __$$\ $$$$$$$ |$$ | \__|$$ / $$$$$$$ | $$ | $$ |$$ | $$ |$$ | $$ | \____$$\ $$ | $$ |$$ __$$ |$$ | $$ | $$ __$$ | $$$$$$$ |\$$$$$$ |$$ | $$ |$$$$$$$ |$$$$$$$ |\$$$$$$$ |$$ | \$$$$$$$\\$$$$$$$ | \_______/ \______/ \__| \__|\_______/ \_______/ \_______|\__| \_______|\_______| */ #include <bits/stdc++.h> using namespace std; #define PB push_back #define MP make_pair #define INS insert #define LB lower_bound #define UB upper_bound #define pii pair <int,int> #define pll pair <long long, long long> #define X first #define Y second #define _ << " " << #define sz(x) (int)x.size() #define all(a) (a).begin(),(a).end() #define FOR(i, a, b) for (int i = (a); i < (b); ++i) #define FORD(i, a, b) for (int i = (a); i > (b); --i) #define FORA(i, x) for (auto &i : x) #define REP(i, n) FOR(i, 0, n) #define BITS(x) __builtin_popcount(x) #define SQ(a) (a) * (a) #define TRACE(x) cout << #x " = " << (x) << '\n'; #define YES cout << "YES\n" #define NO cout << "NO\n" #define umap unordered_map typedef long long ll; typedef long double ld; typedef vector <int> vi; typedef vector <pii> vpi; typedef vector <ll> vll; typedef vector <pll> vpl; typedef vector <double> vd; typedef vector <ld> vld; typedef vector<string> vs; //((float) t)/CLOCKS_PER_SEC const int MOD = 1e9 + 7; const double PI = acos(-1); const int INF = 1e9 + 10; const ll INFL = 2e12 + 10; const int ABC = 30; const int dx[] = {-1, 1, 0, 0}; const int dy[] = {0, 0, -1, 1}; const int dox[] = {-1, 1, 0, 0, -1, -1, 1, 1}; const int doy[] = {0, 0, -1, 1, -1, 1, -1, 1}; inline int sum(int a, int b){ if (a + b < 0) return (a + b + MOD) % MOD; return (a + b) % MOD; } inline void add(int &a, int b){ a = sum(a, b); } inline int mul(ll a, ll b){ return ((a % MOD) * ((ll)b % MOD)) % MOD; } inline int sub(int a, int b){ return (a - b + MOD) % MOD; } inline int fast_pot(ll pot, ll n){ ll ret = 1; while (n){ if (n & 1LL) ret = (ret * pot) % MOD; pot = (pot * pot) % MOD; n >>= 1LL; } return ret; } inline int divide(int a, int b){ return mul(a, fast_pot(b, MOD - 2)); } ll lcm(ll a, ll b){ return abs(a * b) / __gcd(a, b); } inline double ccw(pii A, pii B, pii C){ return (A.X * B.Y) - (A.Y * B.X) + (B.X * C.Y) - (B.Y * C.X) + (C.X * A.Y) - (C.Y * A.X); } inline int CCW(pii A, pii B, pii C){ double val = ccw(A, B, C); double eps = max(max(abs(A.X), abs(A.Y)), max(max(abs(B.X), abs(B.Y)), max(abs(C.X), abs(C.Y)))) / 1e9; if (val <= -eps) return -1; if (val >= eps) return 1; return 0; } void to_upper(string &x){ REP(i, sz(x)) x[i] = toupper(x[i]); } void to_lower(string &x){ REP(i, sz(x)) x[i] = tolower(x[i]); } string its(ll x){ if (x == 0) return "0"; string ret = ""; while (x > 0){ ret += (x % 10) + '0'; x /= 10; } reverse(all(ret)); return ret; } ll sti(string s){ ll ret = 0; REP(i, sz(s)){ ret *= 10; ret += (s[i] - '0'); } return ret; } const ll M = 1e9 + 1; const int N = 1e5 + 10; struct pravac{ ll a, b; }; ll f(pravac p, ll x){ return p.a * x + p.b; } struct node { pravac p; node *l, *r; int vrijeme = 0; node(){ l = r = NULL; p.a = 0, p.b = INFL; } } *root; ll n, st[N], dp[N], r[N], s[N], v[N]; vpl e[N]; int idx = 1; struct LiChao{ vector <node*> roots; map <ll, bool> need; int off; void init(ll n, ll v[]){ for (off = 1; off < M; off *= 2); root = new node(); FOR(i, 2, n + 1) popuni(v[i]); build(root, 1); roots.PB(root); } void popuni(int x){ need[x + off] = 1; for (int i = (x + off) / 2; i > 0; i /= 2){ //cout << i << '\n'; need[i] = 1; } } void build(node *cvor, int id){ if (!need[id]) return; pravac p; p.a = 0, p.b = 0; cvor -> p = p; if (need[id * 2]){ cvor -> l = new node(); build(cvor -> l, id * 2); } if (need[id * 2 + 1]){ cvor -> r = new node(); build(cvor -> r, id * 2 + 1); } } node *update(node *cvor, int lo, int hi, pravac p){ node *novi = new node(); if (cvor != NULL) *novi = *cvor; cvor = novi; // if (cvor -> l != NULL) // cvor -> l -> p = cvor -> p; // if (cvor -> r != NULL) // cvor -> r -> p = cvor -> p; int m = (lo + hi) / 2; //cout << m _ cvor -> p.a _ cvor -> p.b << '\n'; bool left = (f(p, lo) < f(cvor -> p, lo)); bool mid = (f(p, m) < f(cvor -> p, m)); if (mid) cvor -> p = p; if (hi - lo == 1) return cvor; if (left != mid){ if (cvor -> l != NULL) cvor -> l = update(cvor -> l, lo, m, p); } else { if (cvor -> r != NULL) cvor -> r = update(cvor -> r, m, hi, p); } return cvor; } ll query(node *cvor, int lo, int hi, ll x){ int m = (lo + hi) / 2; ll curr = f(cvor -> p, x); if (hi - lo == 1) return curr; // if (cvor -> l != NULL) // cvor -> l -> p = cvor -> p; // if (cvor -> r != NULL) // cvor -> r -> p = cvor -> p; if (x < m){ if (cvor -> l == NULL) return curr; return min(curr, query(cvor -> l, lo, m, x)); } else { if (cvor -> r == NULL) return curr; return min(curr, query(cvor -> r, m, hi, x)); } } ll get(ll x){ return query(roots.back(), 1, M, x); } void Add(pravac p){ roots.PB(update(roots.back(), 1, M, p)); } void roll_back(int t){ assert(t <= sz(roots)); roots.resize(t); } } T; void dfs(int node, int dad){ st[node] = idx++; FORA(nxt, e[node]){ if (nxt.X == dad) continue; dfs(nxt.X, node); } } void solve(int node, int dad, ll l, int k){ if (dad != -1) dp[node] = s[node] + v[node] * l + T.get(v[node]); dp[node] = min(dp[node], v[node] * l + s[node]); //if (dad != -1){ pravac p; p.a = -l, p.b = dp[node]; T.Add(p); //} FORA(nxt, e[node]){ if (nxt.X == dad) continue; T.roll_back(k); solve(nxt.X, node, l + nxt.Y, k + 1); } } // void test(){ // T.init(M); // pravac p; // p.a = -20, p.b = 206; // T.Add(p); // //cout << T.get(30) << '\n'; // } int main () { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); //test(); cin >> n; REP(i, n - 1){ int x, y; cin >> x >> y; ll w; cin >> w; e[x].PB({y, w}); e[y].PB({x, w}); } FOR(i, 2, n + 1) cin >> s[i] >> v[i]; T.init(n, v); dfs(1, -1); solve(1, -1, 0, 1); FOR(i, 2, n + 1) cout << dp[i] << ' '; cout << '\n'; return 0; }
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