이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "tickets.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
#define X first
#define Y second
#define ALL(v) v.begin(),v.end()
#define SZ(a) ((int)a.size())
#define pb push_back
const ll INF=1e18;
struct mode
{
int x,i,j;
bool operator<(const mode &a)const{
return x<a.x;
}
};
ll find_maximum(int k, vector<vector<int>> x)
{
int n = x.size();
int m = x[0].size();
ll rt=0;
vector<vector<int>> answer(n,vector<int>(m,-1));
vector<vector<int>> used(n,vector<int>(m,0));
vector<int> cnt(n,0),num(n,0),nw(n,0),tp(n,0);
vector<mode> v;
for(int i=0;i<n;++i)
for(int j=0;j<m;++j)
v.pb(mode{x[i][j],i,j});
sort(ALL(v));
for(int i=n*m/2;i<SZ(v);++i)
++cnt[v[i].i];
for(int i=0;i<n;++i)
nw[i]=m-cnt[i],num[i]=i,tp[i]=cnt[i];
for(int i=0;i<m;++i)
{
sort(ALL(num),[&](int a,int b){return cnt[a]>cnt[b];});
for(int j=0;j<n/2;++j)
rt+=x[num[j]][m-tp[num[j]]+(--cnt[num[j]])],answer[num[j]][m-tp[num[j]]+cnt[num[j]]]=i;
for(int j=n/2;j<n;++j)
rt-=x[num[j]][--nw[num[j]]],answer[num[j]][nw[num[j]]]=i;
}
allocate_tickets(answer);
return rt;
}
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