이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "tickets.h"
#include <vector>
#include <bits/stdc++.h>
using namespace std;
long long find_maximum(int k, vector<vector<int>> x) {
int n = x.size();
int m = x[0].size();
vector<vector<int>> answer(n, vector<int>(m, -1));
long long ret = 0;
int mxp = n / 2 * k;
int M[n], P[n];
if (k < m)
{
pair<long long, int> mx[n + 1][mxp + 1];
for (int i = 0; i <= n; i++)
for (int j = 0; j <= mxp; j++)
mx[i][j] = { -1e18, 0};
long long del[n][k + 1];
for (int i = 0; i < n; i++)
{
long long d = 0;
for (int c = 0; c < k; c++)
d -= x[i][c];
for (int p = 0; p <= k; p++)
{
del[i][p] = d;
d += x[i][k - 1 - p];
d += x[i][m - 1 - p];
}
}
mx[0][0] = {0, 0};
for (int i = 1; i <= n; i++)
{
for (int a = 0; a <= mxp; a++)
{
int lo = 0;
int hi = min(k, a);
while (hi - lo + 1 >= 5)
{
int p = (lo + hi) / 2;
int p1 = p + 1;
long long v = mx[i - 1][a - p].first + del[i - 1][p];
long long v1 = mx[i - 1][a - p1].first + del[i - 1][p1];
if (v1 >= v)
lo = p1;
else
hi = p;
}
for (int p = lo; p <= hi; p++)
{
mx[i][a] = max(mx[i][a], {mx[i - 1][a - p].first + del[i - 1][p], p});
}
}
}
int p = mxp;
ret = mx[n][p].first;
for (int i = n - 1; i >= 0; i--)
{
int pp = mx[i + 1][p].second;
p -= pp;
P[i] = pp;
M[i] = k - P[i];
}
}
else
{
vector<pair<int, int>>A;
for (int i = 0; i < n; i++)
{
M[i] = P[i] = 0;
for (int j = 0; j < m; j++)
A.push_back({x[i][j], i});
}
sort(A.begin(), A.end());
for (int i = 0; i < (int)A.size() / 2; i++)
{
ret -= A[i].first;
M[A[i].second]++;
}
for (int i = (int)A.size() / 2; i < (int)A.size(); i++)
{
ret += A[i].first;
P[A[i].second]++;
}
}
int a[n];
int b[n];
for (int i = 0; i < n; i++)
{
a[i] = 0;
b[i] = m - 1;
}
for (int g = 0; g < k; g++)
{
pair<int, int>x[n];
for (int i = 0; i < n; i++)
x[i] = {P[i], i};
sort(x, x + n);
for (int i = 0; i < n / 2; i++)
{
int id = x[i].second;
answer[id][a[id]] = g;
a[id]++;
M[id]--;
}
for (int i = n / 2; i < n; i++)
{
int id = x[i].second;
answer[id][b[id]] = g;
b[id]--;
P[id]--;
}
}
allocate_tickets(answer);
return ret;
}
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