제출 #301557

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
301557		Batyr	카니발 티켓 (IOI20_tickets)	C++17	25 / 100	675 ms	62968 KiB

tickets

#include<bits/stdc++.h>
#ifndef LOCAL
#include "tickets.h"
#endif
using namespace std;
#define pb push_back
#define ff first
#define ss second
#define sz(a) (int)a.size()
typedef long long ll;
typedef vector<int> vi;
typedef pair<int,int> pii;
const ll inf=1e18;
const int mod=1e9+7;
const int maxn=2e3+5;

int n,m,num[maxn][3],cnt[3];
int us[maxn],t,an,x;
ll ans;
vi b[maxn][3],d,v;
vector<vector<int>>s;
priority_queue<pii> g[3];

#ifdef LOCAL
void allocate_tickets(vector<vi> a){
	return;
}
#endif

void f(int tp,int round){
	memset(us,0,sizeof(us));
	t = 0;
	d.clear();
	while(!g[tp].empty()){
		if(t == n/2) break;
		x=g[tp].top().ss;
		g[tp].pop();
		us[x] = 1;
		num[x][tp]--;
		b[x][tp].pb(round);
		if(num[x][tp] > 0) d.pb(x);
		t++;
	}
	ans += t;
	for(auto i : d) g[tp].push({num[i][tp],i});
	if(tp==1) an=0;
	else an=1;
	for(int i = 0;i < n;i++){
		if(us[i] or num[i][an]==0) continue;
		num[i][an]--;
		b[i][an].pb(round);
	}
}

ll find_maximum(int k,vector<vector<int>>x){
	n=sz(x);
	m=sz(x[0]);
	s.resize(n);
	for(int i = 0;i < n;i++) s[i].resize(m);
	if(m==1){
		for(int i = 0;i < n;i++) v.pb(x[i][0]);
		sort(v.begin(),v.end());
		for(int i = 0;i < n;i++) ans += abs(v[n/2]-v[i]);
		allocate_tickets(s);
		return ans;
	}
	for(int i = 0;i < n;i++){
		
		for(int j = 0;j < m;j++) num[i][x[i][j]]++;
		
		if(num[i][0]) g[0].push({num[i][0],i});
		if(num[i][1]) g[1].push({num[i][1],i});
		
		cnt[0] += num[i][0];
		cnt[1] += num[i][1];
	}
	for(int i = 0;i < k;i++){
		if(cnt[0] < cnt[1]) f(0,i);
		else f(1,i);
	}
	for(int i = 0;i < n;i++){
		for(int j = 0;j < m;j++){
			if(sz(b[i][x[i][j]])){
				s[i][j] = b[i][x[i][j]].back();
				b[i][x[i][j]].pop_back();
			}
			else s[i][j] = -1;
		}
	}
	allocate_tickets(s);
	return ans;
}

#ifdef LOCAL
int main(){
	int n,m,k;
	cin >> n >> m >> k;
	vector<vi> c;
	c.resize(n);
	for(int i = 0;i < n;i++){
		c[i].resize(m);
		for(int j = 0;j < m;j++) cin >> c[i][j];
	}
	cout<<find_maximum(k,c)<<'\n';
}
#endif

• Subtask 1: 11 / 11
• Subtask 2: 0 / 16
• Subtask 3: 14 / 14
• Subtask 4: 0 / 14
• Subtask 5: 0 / 12
• Subtask 6: 0 / 23
• Subtask 7: 0 / 10