This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#ifdef imeimi
#include <vector>
int construct(std::vector<std::vector<int>> p);
void build(std::vector<std::vector<int>> b);
#include <vector>
#include <cassert>
#include <cstdio>
#include <cstdlib>
#include <string>
#define n N
static int n;
static std::vector<std::vector<int>> p;
static std::vector<std::vector<int>> b;
static bool called = false;
static void check(bool cond, std::string message) {
if (!cond) {
printf("%s\n", message.c_str());
fclose(stdout);
exit(0);
}
}
void build(std::vector<std::vector<int>> _b) {
check(!called, "build is called more than once");
called = true;
check((int)_b.size() == n, "Invalid number of rows in b");
for (int i = 0; i < n; i++) {
check((int)_b[i].size() == n, "Invalid number of columns in b");
}
b = _b;
}
int main() {
assert(scanf("%d", &n) == 1);
p.resize(n);
for (int i = 0; i < n; i++) {
p[i].resize(n);
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
assert(scanf("%d", &p[i][j]) == 1);
}
}
fclose(stdin);
int possible = construct(p);
check(possible == 0 || possible == 1, "Invalid return value of construct");
if (possible == 1) {
check(called, "construct returned 1 without calling build");
} else {
check(!called, "construct called build but returned 0");
}
printf("%d\n", possible);
if (possible == 1) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (j) {
printf(" ");
}
printf("%d", b[i][j]);
}
printf("\n");
}
}
fclose(stdout);
}
#undef n
#else
#include "supertrees.h"
#endif
#include <bits/stdc++.h>
using namespace std;
typedef pair<int, int> pii;
static vector<int> lst;
static int n, edge[1000][1000];
static bool vis[1000];
static int idx[1000];
static void dfs(int x, int c) {
vis[x] = 1;
lst.push_back(x);
for (int i = 0; i < n; ++i) {
if (!edge[x][i] || edge[x][i] > c || vis[i]) continue;
dfs(i, c);
}
}
int construct(vector<vector<int>> p) {
n = p.size();
for (int i = 0; i < n; ++i) for (int j = 0; j < n; ++j) {
if (p[i][j] == 3) return 0;
edge[i][j] = p[i][j];
}
vector<vector<int>> ans(n, vector<int>(n, 0));
for (int i = 0; i < n; ++i) {
if (vis[i]) continue;
dfs(i, 1);
for (int j : lst) for (int k : lst) if (edge[j][k] != 1) return 0;
for (int j : lst) idx[j] = lst[0];
for (int j = 1; j < int(lst.size()); ++j) {
int x = lst[j - 1], y = lst[j];
ans[x][y] = ans[y][x] = 1;
}
lst.clear();
}
memset(vis, 0, sizeof(vis));
for (int i = 0; i < n; ++i) {
if (vis[i]) continue;
dfs(i, 2);
for (int j : lst) for (int k : lst) if (!edge[j][k]) return 0;
vector<int> nxt;
for (int j : lst) if (idx[j] == j) nxt.push_back(j);
lst.clear();
if (int(nxt.size()) == 2) return 0;
if (int(nxt.size()) <= 1) continue;
for (int j = 0; j < int(nxt.size()); ++j) {
int x = nxt[j], y = nxt[(j + 1) % int(nxt.size())];
ans[x][y] = ans[y][x] = 1;
}
}
build(ans);
return 1;
}
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