oj.uz

답안 #300405

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
300405 2020-09-17T06:50:58 Z bacegen4o Joker (BOI20_joker) C
36 / 100
 2000 ms 6264 KB 
#pragma GCC optimize "-O3"
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
#include<assert.h>
#include<stdbool.h>
#include<limits.h>
#define swap(a,b) do{ __typeof(a) tp; tp=a; a=b; b=tp; }while(0)
typedef struct{
  int first, second;
}pair;
pair newpair(int a, int b){
  return(pair){a,b};
}

#ifndef STB_STRETCHY_BUFFER_H_INCLUDED
#define STB_STRETCHY_BUFFER_H_INCLUDED
#ifndef NO_STRETCHY_BUFFER_SHORT_NAMES
#define sb_free   stb_sb_free
#define sb_push   stb_sb_push
#define sb_count  stb_sb_count
#define sb_add    stb_sb_add
#define sb_last   stb_sb_last
#endif
#define stb_sb_free(a)         ((a) ? free(stb__sbraw(a)),0 : 0)
#define stb_sb_push(a,v)       (stb__sbmaybegrow(a,1), (a)[stb__sbn(a)++] = (v))
#define stb_sb_count(a)        ((a) ? stb__sbn(a) : 0)
#define stb_sb_add(a,n)        (stb__sbmaybegrow(a,n), stb__sbn(a)+=(n), &(a)[stb__sbn(a)-(n)])
#define stb_sb_last(a)         ((a)[stb__sbn(a)-1])
#define stb__sbraw(a) ((int *) (a) - 2)
#define stb__sbm(a)   stb__sbraw(a)[0]
#define stb__sbn(a)   stb__sbraw(a)[1]
#define stb__sbneedgrow(a,n)  ((a)==0 || stb__sbn(a)+(n) >= stb__sbm(a))
#define stb__sbmaybegrow(a,n) (stb__sbneedgrow(a,(n)) ? stb__sbgrow(a,n) : 0)
#define stb__sbgrow(a,n)      (*((void **)&(a)) = stb__sbgrowf((a), (n), sizeof(*(a))))

static void*stb__sbgrowf(void*arr, int increment, int itemsize){
  int dbl_cur = arr ? 2*stb__sbm(arr) : 0;
  int min_needed = stb_sb_count(arr) + increment;
  int m = dbl_cur > min_needed ? dbl_cur : min_needed;
  int*p = (int *) realloc(arr ? stb__sbraw(arr) : 0, itemsize * m + sizeof(int)*2);
  if(p){
    if(!arr)
      p[1] = 0;
    p[0] = m;
    return p+2;
  } 
  else {
    #ifdef STRETCHY_BUFFER_OUT_OF_MEMORY
    STRETCHY_BUFFER_OUT_OF_MEMORY;
    #endif
    return(void*)(2*sizeof(int));
  }
}
#endif


#if 1//stb
#define STB_(prefix,name)     stb__##prefix##name
#define stb_declare_sort(FUNCNAME, TYPE)    \
                       void FUNCNAME(TYPE *p, int n)
#define stb_define_sort(FUNCNAME,TYPE,COMPARE) \
                       stb__define_sort(       void, FUNCNAME,TYPE,COMPARE)
#define stb_define_sort_static(FUNCNAME,TYPE,COMPARE) \
                       stb__define_sort(static void, FUNCNAME,TYPE,COMPARE)
#define stb__define_sort(MODE, FUNCNAME, TYPE, COMPARE)                       \
                                                                              \
static void STB_(FUNCNAME,_ins_sort)(TYPE *p, int n)                          \
{                                                                             \
   int i,j;                                                                   \
   for (i=1; i < n; ++i) {                                                    \
      TYPE t = p[i], *a = &t;                                                 \
      j = i;                                                                  \
      while (j > 0) {                                                         \
         TYPE *b = &p[j-1];                                                   \
         int c = COMPARE;                                                     \
         if (!c) break;                                                       \
         p[j] = p[j-1];                                                       \
         --j;                                                                 \
      }                                                                       \
      if (i != j)                                                             \
         p[j] = t;                                                            \
   }                                                                          \
}                                                                             \
                                                                              \
static void STB_(FUNCNAME,_quicksort)(TYPE *p, int n)                         \
{                                                                             \
   /* threshold for transitioning to insertion sort */                       \
   while (n > 12) {                                                           \
      TYPE *a,*b,t;                                                           \
      int c01,c12,c,m,i,j;                                                    \
                                                                              \
      /* compute median of three */                                           \
      m = n >> 1;                                                             \
      a = &p[0];                                                              \
      b = &p[m];                                                              \
      c = COMPARE;                                                            \
      c01 = c;                                                                \
      a = &p[m];                                                              \
      b = &p[n-1];                                                            \
      c = COMPARE;                                                            \
      c12 = c;                                                                \
      /* if 0 >= mid >= end, or 0 < mid < end, then use mid */                \
      if (c01 != c12) {                                                       \
         /* otherwise, we'll need to swap something else to middle */         \
         int z;                                                               \
         a = &p[0];                                                           \
         b = &p[n-1];                                                         \
         c = COMPARE;                                                         \
         /* 0>mid && mid<n:  0>n => n; 0<n => 0 */                            \
         /* 0<mid && mid>n:  0>n => 0; 0<n => n */                            \
         z = (c == c12) ? 0 : n-1;                                            \
         t = p[z];                                                            \
         p[z] = p[m];                                                         \
         p[m] = t;                                                            \
      }                                                                       \
      /* now p[m] is the median-of-three */                                   \
      /* swap it to the beginning so it won't move around */                  \
      t = p[0];                                                               \
      p[0] = p[m];                                                            \
      p[m] = t;                                                               \
                                                                              \
      /* partition loop */                                                    \
      i=1;                                                                    \
      j=n-1;                                                                  \
      for(;;) {                                                               \
         /* handling of equality is crucial here */                           \
         /* for sentinels & efficiency with duplicates */                     \
         b = &p[0];                                                           \
         for (;;++i) {                                                        \
            a=&p[i];                                                          \
            c = COMPARE;                                                      \
            if (!c) break;                                                    \
         }                                                                    \
         a = &p[0];                                                           \
         for (;;--j) {                                                        \
            b=&p[j];                                                          \
            c = COMPARE;                                                      \
            if (!c) break;                                                    \
         }                                                                    \
         /* make sure we haven't crossed */                                   \
         if (i >= j) break;                                                   \
         t = p[i];                                                            \
         p[i] = p[j];                                                         \
         p[j] = t;                                                            \
                                                                              \
         ++i;                                                                 \
         --j;                                                                 \
      }                                                                       \
      /* recurse on smaller side, iterate on larger */                        \
      if (j < (n-i)) {                                                        \
         STB_(FUNCNAME,_quicksort)(p,j);                                       \
         p = p+i;                                                             \
         n = n-i;                                                             \
      } else {                                                                \
         STB_(FUNCNAME,_quicksort)(p+i, n-i);                                  \
         n = j;                                                               \
      }                                                                       \
   }                                                                          \
}                                                                             \
                                                                              \
MODE FUNCNAME(TYPE *p, int n)                                                 \
{                                                                             \
   STB_(FUNCNAME, _quicksort)(p, n);                                           \
   STB_(FUNCNAME, _ins_sort)(p, n);                                            \
}
#endif


stb_define_sort(sort_f, pair, a->first==b->first? a->second < b->second : a->first < b->first)

inline double sqrt(double x){
  __asm__ ("fsqrt" : "+t" (x));
  return x;
}
inline int max(int a,int b){return a>b?a:b;}
///////////////////////////////////
enum{MAXN = 200005};
enum{MAXM = 200005};
enum{MAXQ = 200005};
int comp[MAXN], h[MAXN];
bool col_switch[MAXN];
int n_mem, mem_cv[MAXM], mem_cu[MAXM], mem_hcu[MAXM];
bool mem_swcv[MAXM];
int N, M, Q;
int E[2][MAXM], queries[2][MAXQ], res[MAXQ];
int*inds;


void init_dsu(int n){
    for(int i=0; i<n; i++){
        comp[i] = i;
        h[i] = 0;
        col_switch[i] = 0;
    }
    n_mem = 0;
}
pair find(int v){
    bool col = col_switch[v];
    while(comp[v] != v){
        v = comp[v];
        col ^= 1;
        col ^= col_switch[v];
    }
    return newpair(v, col);
}
void merge(int v, int u){
    pair ansv = find(v),
         ansu = find(u);
    int cv = ansv.first,
        cu = ansu.first;
    bool colv = ansv.second,
         colu = ansu.second;
    if(cv != cu){
        if(h[cv] > h[cu]){
            swap(cv, cu);
            swap(v, u);
        }
        mem_cv  [n_mem] = cv;
        mem_cu  [n_mem] = cu;
        mem_hcu [n_mem] = h[cu];
        mem_swcv[n_mem] = col_switch[cv];
        n_mem++;
        comp[cv] = cu;
        if(h[cv] == h[cu])
           h[cu]++;
        col_switch[cv] = (colv != colu);
    }
    else{
        mem_cv[n_mem] = -1;
        n_mem++;
    }
}
int check(int v, int u){
    pair ansv = find(v),
         ansu = find(u);
    int cv = ansv.first,
        cu = ansu.first;
    bool colv = ansv.second,
         colu = ansu.second;
    if(cv != cu)
        return 2;
    if(colv == colu)
        return -1;
    return 1;
}
void rollback(int k){
    while(k--){
        n_mem--;
        int cv = mem_cv[n_mem],
            cu = mem_cu[n_mem];
        bool swcv = mem_swcv[n_mem];
        if(cv == -1)
            continue;
        comp[cv] = cv;
        h[cu] = cu;
        col_switch[cv] = swcv;
    }
}
void solve_for_inds(int e_left_next){
    int k = sb_count(inds);
    pair v[k];
    for(int i=0; i<k; i++){
        int ind = inds[i];
        v[i] = newpair(-queries[1][ind], ind);
    }
    sort_f(v, k);
    int e_right_next = M-1, steps = 0;
    bool got_cycle = false;
    for(int i = 0; i < k; i++){
        int ind = v[i].second;
        int L = queries[0][ind], R = queries[1][ind];
        if(!got_cycle){
            while(e_right_next > R){
                int status = check(E[0][e_right_next], E[1][e_right_next]);
                if(status == -1){
                    got_cycle = true;
                    break;
                }
                merge(E[0][e_right_next], E[1][e_right_next]);
                e_right_next--;
                steps++;
            }
        }
        bool got_cycle_inner = got_cycle;
        int steps_inner = 0;
        if(!got_cycle_inner){
            for (int e = e_left_next; e < L; e++) {
                int status = check(E[0][e], E[1][e]);
                if(status == -1){
                    got_cycle_inner = true;
                    break;
                }
                merge(E[0][e], E[1][e]);
                steps_inner++;
            }
        }
        res[ind] = (int)(got_cycle || got_cycle_inner);
        rollback(steps_inner);
    }
    rollback(steps);
}
void solve(){
    int B = max((int)(M / sqrt(Q)), 1);
    pair v[Q];
    for(int i = 0; i < Q; i++){
        v[i] = newpair(queries[0][i] / B, i);
    }
    sort_f(v, Q);
    init_dsu(N);
    int e_left_next = 0;
    bool got_cycle = false;
    if(inds)
        sb_free(inds);
    inds = NULL;
    for(int i=0; i<Q; i++){
        sb_push(inds, v[i].second);
        if(i + 1 == Q || v[i].first != v[i+1].first){
            while(!got_cycle && e_left_next < v[i].first * B){
                int status = check(E[0][e_left_next], E[1][e_left_next]);
                if(status == -1){
                    got_cycle = true;
                    break;
                }
                merge(E[0][e_left_next], E[1][e_left_next]);
                e_left_next++;
            }
            if(got_cycle){
                for(int j = 0; j<sb_count(inds); j++){
                    int ind = inds[j];
                    res[ind] = 1;
                }
            }
            else{
                solve_for_inds(e_left_next);
            }
            if(inds)
                sb_free(inds);
            inds = NULL;
        }
    }
}
int main(){
    while(scanf("%d%d%d", &N, &M, &Q)==3){
        for(int i = 0; i < M; i++){
            scanf("%d %d", &E[0][i], &E[1][i]);
            E[0][i]--;
            E[1][i]--;
        }
        for(int i = 0; i < Q; i++){
            scanf("%d %d", &queries[0][i], &queries[1][i]);
            queries[0][i]--;
            queries[1][i]--;
        }
        solve();
        for(int i = 0; i < Q; i++){
            if (res[i])
                puts("YES");
            else
                puts("NO");
        }
    }
    return 0;
}

Compilation message

Joker.c: In function 'main':
Joker.c:347:13: warning: ignoring return value of 'scanf', declared with attribute warn_unused_result [-Wunused-result]
  347 |             scanf("%d %d", &E[0][i], &E[1][i]);
      |             ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Joker.c:352:13: warning: ignoring return value of 'scanf', declared with attribute warn_unused_result [-Wunused-result]
  352 |             scanf("%d %d", &queries[0][i], &queries[1][i]);
      |             ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
5 Correct 0 ms 384 KB Output is correct
6 Correct 0 ms 384 KB Output is correct
7 Correct 1 ms 384 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 1 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 1 ms 512 KB Output is correct
13 Correct 1 ms 384 KB Output is correct
14 Correct 1 ms 384 KB Output is correct
15 Correct 1 ms 384 KB Output is correct
16 Correct 1 ms 384 KB Output is correct
17 Correct 1 ms 384 KB Output is correct
18 Correct 1 ms 384 KB Output is correct
19 Correct 1 ms 384 KB Output is correct
20 Correct 1 ms 384 KB Output is correct
21 Correct 1 ms 384 KB Output is correct
22 Correct 1 ms 384 KB Output is correct
23 Correct 1 ms 384 KB Output is correct
24 Correct 1 ms 384 KB Output is correct
25 Correct 1 ms 384 KB Output is correct
26 Correct 1 ms 384 KB Output is correct
27 Correct 1 ms 384 KB Output is correct
28 Correct 1 ms 384 KB Output is correct

Subtask #2
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
5 Correct 0 ms 384 KB Output is correct
6 Correct 0 ms 384 KB Output is correct
7 Correct 1 ms 384 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 1 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 1 ms 512 KB Output is correct
13 Correct 1 ms 384 KB Output is correct
14 Correct 1 ms 384 KB Output is correct
15 Correct 1 ms 384 KB Output is correct
16 Correct 1 ms 384 KB Output is correct
17 Correct 1 ms 384 KB Output is correct
18 Correct 1 ms 384 KB Output is correct
19 Correct 1 ms 384 KB Output is correct
20 Correct 1 ms 384 KB Output is correct
21 Correct 1 ms 384 KB Output is correct
22 Correct 1 ms 384 KB Output is correct
23 Correct 1 ms 384 KB Output is correct
24 Correct 1 ms 384 KB Output is correct
25 Correct 1 ms 384 KB Output is correct
26 Correct 1 ms 384 KB Output is correct
27 Correct 1 ms 384 KB Output is correct
28 Correct 1 ms 384 KB Output is correct
29 Correct 3 ms 384 KB Output is correct
30 Correct 3 ms 384 KB Output is correct
31 Correct 2 ms 384 KB Output is correct
32 Correct 2 ms 384 KB Output is correct
33 Correct 2 ms 384 KB Output is correct
34 Correct 2 ms 384 KB Output is correct
35 Correct 3 ms 384 KB Output is correct
36 Correct 2 ms 384 KB Output is correct
37 Correct 3 ms 512 KB Output is correct
38 Correct 4 ms 512 KB Output is correct
39 Correct 3 ms 512 KB Output is correct
40 Correct 2 ms 384 KB Output is correct
41 Correct 2 ms 384 KB Output is correct
42 Correct 2 ms 384 KB Output is correct
43 Correct 2 ms 384 KB Output is correct
44 Correct 2 ms 384 KB Output is correct
45 Correct 2 ms 384 KB Output is correct
46 Correct 2 ms 512 KB Output is correct
47 Correct 2 ms 384 KB Output is correct
48 Correct 2 ms 384 KB Output is correct
49 Correct 2 ms 384 KB Output is correct
50 Correct 3 ms 384 KB Output is correct
51 Correct 2 ms 384 KB Output is correct
52 Correct 2 ms 384 KB Output is correct
53 Correct 2 ms 384 KB Output is correct
54 Correct 3 ms 384 KB Output is correct

Subtask #3
0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Execution timed out 2049 ms 4984 KB Time limit exceeded
4 Halted 0 ms 0 KB -

Subtask #4
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
5 Correct 0 ms 384 KB Output is correct
6 Correct 0 ms 384 KB Output is correct
7 Correct 1 ms 384 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 1 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 1 ms 512 KB Output is correct
13 Correct 1 ms 384 KB Output is correct
14 Correct 1 ms 384 KB Output is correct
15 Correct 1 ms 384 KB Output is correct
16 Correct 1 ms 384 KB Output is correct
17 Correct 1 ms 384 KB Output is correct
18 Correct 1 ms 384 KB Output is correct
19 Correct 1 ms 384 KB Output is correct
20 Correct 1 ms 384 KB Output is correct
21 Correct 1 ms 384 KB Output is correct
22 Correct 1 ms 384 KB Output is correct
23 Correct 1 ms 384 KB Output is correct
24 Correct 1 ms 384 KB Output is correct
25 Correct 1 ms 384 KB Output is correct
26 Correct 1 ms 384 KB Output is correct
27 Correct 1 ms 384 KB Output is correct
28 Correct 1 ms 384 KB Output is correct
29 Execution timed out 2049 ms 4984 KB Time limit exceeded
30 Halted 0 ms 0 KB -

Subtask #5
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
5 Correct 0 ms 384 KB Output is correct
6 Correct 0 ms 384 KB Output is correct
7 Correct 1 ms 384 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 1 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 1 ms 512 KB Output is correct
13 Correct 1 ms 384 KB Output is correct
14 Correct 1 ms 384 KB Output is correct
15 Correct 1 ms 384 KB Output is correct
16 Correct 1 ms 384 KB Output is correct
17 Correct 1 ms 384 KB Output is correct
18 Correct 1 ms 384 KB Output is correct
19 Correct 1 ms 384 KB Output is correct
20 Correct 1 ms 384 KB Output is correct
21 Correct 1 ms 384 KB Output is correct
22 Correct 1 ms 384 KB Output is correct
23 Correct 1 ms 384 KB Output is correct
24 Correct 1 ms 384 KB Output is correct
25 Correct 1 ms 384 KB Output is correct
26 Correct 1 ms 384 KB Output is correct
27 Correct 1 ms 384 KB Output is correct
28 Correct 1 ms 384 KB Output is correct
29 Correct 3 ms 384 KB Output is correct
30 Correct 3 ms 384 KB Output is correct
31 Correct 2 ms 384 KB Output is correct
32 Correct 2 ms 384 KB Output is correct
33 Correct 2 ms 384 KB Output is correct
34 Correct 2 ms 384 KB Output is correct
35 Correct 3 ms 384 KB Output is correct
36 Correct 2 ms 384 KB Output is correct
37 Correct 3 ms 512 KB Output is correct
38 Correct 4 ms 512 KB Output is correct
39 Correct 3 ms 512 KB Output is correct
40 Correct 2 ms 384 KB Output is correct
41 Correct 2 ms 384 KB Output is correct
42 Correct 2 ms 384 KB Output is correct
43 Correct 2 ms 384 KB Output is correct
44 Correct 2 ms 384 KB Output is correct
45 Correct 2 ms 384 KB Output is correct
46 Correct 2 ms 512 KB Output is correct
47 Correct 2 ms 384 KB Output is correct
48 Correct 2 ms 384 KB Output is correct
49 Correct 2 ms 384 KB Output is correct
50 Correct 3 ms 384 KB Output is correct
51 Correct 2 ms 384 KB Output is correct
52 Correct 2 ms 384 KB Output is correct
53 Correct 2 ms 384 KB Output is correct
54 Correct 3 ms 384 KB Output is correct
55 Correct 132 ms 4088 KB Output is correct
56 Correct 336 ms 6264 KB Output is correct
57 Correct 154 ms 5752 KB Output is correct
58 Correct 121 ms 4088 KB Output is correct
59 Correct 92 ms 4088 KB Output is correct
60 Correct 107 ms 4584 KB Output is correct
61 Correct 135 ms 4088 KB Output is correct
62 Correct 164 ms 4856 KB Output is correct
63 Correct 155 ms 3576 KB Output is correct
64 Correct 191 ms 4344 KB Output is correct
65 Correct 208 ms 4856 KB Output is correct

Subtask #6
0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
5 Correct 0 ms 384 KB Output is correct
6 Correct 0 ms 384 KB Output is correct
7 Correct 1 ms 384 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 1 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 1 ms 512 KB Output is correct
13 Correct 1 ms 384 KB Output is correct
14 Correct 1 ms 384 KB Output is correct
15 Correct 1 ms 384 KB Output is correct
16 Correct 1 ms 384 KB Output is correct
17 Correct 1 ms 384 KB Output is correct
18 Correct 1 ms 384 KB Output is correct
19 Correct 1 ms 384 KB Output is correct
20 Correct 1 ms 384 KB Output is correct
21 Correct 1 ms 384 KB Output is correct
22 Correct 1 ms 384 KB Output is correct
23 Correct 1 ms 384 KB Output is correct
24 Correct 1 ms 384 KB Output is correct
25 Correct 1 ms 384 KB Output is correct
26 Correct 1 ms 384 KB Output is correct
27 Correct 1 ms 384 KB Output is correct
28 Correct 1 ms 384 KB Output is correct
29 Correct 3 ms 384 KB Output is correct
30 Correct 3 ms 384 KB Output is correct
31 Correct 2 ms 384 KB Output is correct
32 Correct 2 ms 384 KB Output is correct
33 Correct 2 ms 384 KB Output is correct
34 Correct 2 ms 384 KB Output is correct
35 Correct 3 ms 384 KB Output is correct
36 Correct 2 ms 384 KB Output is correct
37 Correct 3 ms 512 KB Output is correct
38 Correct 4 ms 512 KB Output is correct
39 Correct 3 ms 512 KB Output is correct
40 Correct 2 ms 384 KB Output is correct
41 Correct 2 ms 384 KB Output is correct
42 Correct 2 ms 384 KB Output is correct
43 Correct 2 ms 384 KB Output is correct
44 Correct 2 ms 384 KB Output is correct
45 Correct 2 ms 384 KB Output is correct
46 Correct 2 ms 512 KB Output is correct
47 Correct 2 ms 384 KB Output is correct
48 Correct 2 ms 384 KB Output is correct
49 Correct 2 ms 384 KB Output is correct
50 Correct 3 ms 384 KB Output is correct
51 Correct 2 ms 384 KB Output is correct
52 Correct 2 ms 384 KB Output is correct
53 Correct 2 ms 384 KB Output is correct
54 Correct 3 ms 384 KB Output is correct
55 Execution timed out 2049 ms 4984 KB Time limit exceeded
56 Halted 0 ms 0 KB -