oj.uz

Submission #296030

# Submission time Handle Problem Language Result Execution time Memory
296030 2020-09-10T08:06:57 Z ToMmyDong Ancient Books (IOI17_books) C++11
0 / 100
 1 ms 384 KB 
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
#define SZ(i) int(i.size())
#define ALL(i) i.begin(), i.end()
#define MEM(i,a) memset(i, (a), sizeof(i))
#define X first
#define Y second
#define eb emplace_back
#define pb push_back
#ifdef tmd
#define debug(...) fprintf(stderr,"#%d-(%s)=",__LINE__,#__VA_ARGS__);_do(__VA_ARGS__);
template<typename T> void _do (T &&x) {cerr<<x<<endl;}
template<typename T, typename ...S> void _do(T &&x, S &&...y) {cerr<<x<<", ";_do(y...);}
template<typename IT> ostream& __printRng (ostream &os, IT bg, IT ed) {
    for (IT it=bg; it!=ed; it++) {
        if (it!=bg) os << "," << *it;
        else os << "{" << *it;
    }
    return os << "}";
}
template<typename T> ostream &operator << (ostream &os, const pair<T,T> &v) {
    return os << "{" << v.X << "," <<v.Y << "}";
}
template<typename T> ostream &operator << (ostream &os, const vector<T> &v) {
    return __printRng(os, ALL(v));
}
template<typename T> ostream &operator << (ostream &os, const set<T> &v) {
    return __printRng(os, ALL(v));
}
#define IOS()
#else
#define debug(...)
#define endl '\n'
#define IOS() ios_base::sync_with_stdio(0);cin.tie(0);
#endif
#include "books.h"


int n, mn, mx;
ll sum;
vector<int> vis, p;

void dfs (int nd) {
    mn = min(nd, mn);
    mx = max(nd, mx);
    vis[nd] = true;
    sum += abs(nd-p[nd]);
    if (!vis[p[nd]]) {
        dfs(p[nd]);
    }
}

ll minimum_walk(std::vector<int> P, int s) {
    p = P;
    n = SZ(p);
    vis.resize(n);

    vector<pii> rng;
    for (int i=0; i<n; i++) {
        if (!vis[i] && p[i] != i) {
            mn = i;
            mx = i;
            dfs(i);
            rng.eb(mn, mx);
        }
    }

    sort(ALL(rng));
    vector<pii> nrng;

    int lst = -1;
    int L = -1;
    for (pii r : rng) {
        if (r.X > lst) {
            if (L != -1) {
                nrng.eb(L, lst);
            }
            L = r.X;
            lst = r.Y;
        } else {
            lst = max(lst, r.Y);
        }
    }
    if (L) nrng.eb(L, lst);

    debug(nrng);
    debug(sum);

    for (int i=0; i<SZ(nrng); i++) {
        sum += 2 * (nrng[i].X - s);
        s = nrng[i].Y;
    }
	return sum;
}

Subtask #1
0 / 12.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 256 KB Output is correct
2 Correct 1 ms 256 KB Output is correct
3 Correct 0 ms 256 KB Output is correct
4 Correct 1 ms 256 KB Output is correct
5 Correct 0 ms 256 KB Output is correct
6 Correct 1 ms 256 KB Output is correct
7 Correct 0 ms 256 KB Output is correct
8 Correct 1 ms 256 KB Output is correct
9 Incorrect 1 ms 256 KB 3rd lines differ - on the 1st token, expected: '0', found: '-2'
10 Halted 0 ms 0 KB -

Subtask #2
0 / 10.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 256 KB Output is correct
2 Correct 1 ms 256 KB Output is correct
3 Correct 0 ms 256 KB Output is correct
4 Correct 1 ms 256 KB Output is correct
5 Correct 0 ms 256 KB Output is correct
6 Correct 1 ms 256 KB Output is correct
7 Correct 0 ms 256 KB Output is correct
8 Correct 1 ms 256 KB Output is correct
9 Incorrect 1 ms 256 KB 3rd lines differ - on the 1st token, expected: '0', found: '-2'
10 Halted 0 ms 0 KB -

Subtask #3
0 / 28.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 256 KB Output is correct
2 Correct 1 ms 256 KB Output is correct
3 Correct 0 ms 256 KB Output is correct
4 Correct 1 ms 256 KB Output is correct
5 Correct 0 ms 256 KB Output is correct
6 Correct 1 ms 256 KB Output is correct
7 Correct 0 ms 256 KB Output is correct
8 Correct 1 ms 256 KB Output is correct
9 Incorrect 1 ms 256 KB 3rd lines differ - on the 1st token, expected: '0', found: '-2'
10 Halted 0 ms 0 KB -

Subtask #4
0 / 20.0

# Verdict Execution time Memory Grader output
1 Incorrect 1 ms 384 KB 3rd lines differ - on the 1st token, expected: '3304', found: '2744'
2 Halted 0 ms 0 KB -

Subtask #5
0 / 30.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 256 KB Output is correct
2 Correct 1 ms 256 KB Output is correct
3 Correct 0 ms 256 KB Output is correct
4 Correct 1 ms 256 KB Output is correct
5 Correct 0 ms 256 KB Output is correct
6 Correct 1 ms 256 KB Output is correct
7 Correct 0 ms 256 KB Output is correct
8 Correct 1 ms 256 KB Output is correct
9 Incorrect 1 ms 256 KB 3rd lines differ - on the 1st token, expected: '0', found: '-2'
10 Halted 0 ms 0 KB -