제출 #29362

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
29362		cdemirer	Foehn Phenomena (JOI17_foehn_phenomena)	C++14	0 / 100	23 ms	11152 KiB

foehn_phenomena

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<int> vi;
typedef vector<vector<int> > vvi;
typedef vector<pair<int, int> > vii;
typedef vector<vector<pair<int, int> > > vvii;
#define pb(x) push_back(x)
#define mp(x, y) make_pair(x, y)

int N, Q, S, T;
int A[200001];
ll res = 0;
typedef struct Node_ {
	int llim, rlim;
	ll update;
} Node;
const int segsz = 524288;
Node seg[segsz];
int offset = segsz/2;

ll get(int x) {
	x += offset;
	ll ret = 0;
	while (x > 0) {
		ret += seg[x].update;
		x /= 2;
	}
	return ret;
}

void _update(int x, int l, int r, int dy) {
	int llim = seg[x].llim;
	int rlim = seg[x].rlim;
	int mid = (llim + rlim) / 2;
	if (l == llim && r == rlim) seg[x].update += dy;
	else if (l > mid) _update(2*x+1, l, r, dy);
	else if (r <= mid) _update(2*x, l, r, dy);
	else {
		_update(2*x, l, mid, dy);
		_update(2*x+1, mid+1, r, dy);
	}
}
void update(int l, int r, int dy) { _update(1, l, r, dy); }

int main(int argc, char **argv) {

	//freopen("input", "r", stdin);
	//freopen("output", "w", stdout);

	ios_base::sync_with_stdio(0);
	cin.tie(0);

	cin >> N >> Q >> S >> T;
	for (int i = offset; i < segsz; i++) {
		seg[i].llim = seg[i].rlim = i - offset;
		seg[i].update = 0;
	}
	for (int i = offset-1; i > 0; i--) {
		seg[i].llim = seg[2*i].llim;
		seg[i].rlim = seg[2*i+1].rlim;
		seg[i].update = 0;
	}
	for (int i = 0; i < N+1; i++) {
		cin >> A[i];
		seg[i+offset].update = A[i];
	}
	for (int i = 1; i < N+1; i++) {
		if (A[i] == A[i-1]) continue;
		if (A[i] > A[i-1]) res -= S*(A[i]-A[i-1]);
		else res += T*(A[i-1]-A[i]);
	}
	for (int i = 0; i < Q; i++) {
		int l, r, dy; cin >> l >> r >> dy;
		ll a = get(l-1), b = get(l), c = get(r); ll d = (r+1<=N?get(r+1):c);
		ll old_effect = (a>b?T*(a-b):-S*(b-a)) + (c>d?T*(c-d):-S*(d-c));
		update(l, r, dy);
		b += dy; c += dy; if (r+1>N) d = c;
		ll new_effect = (a>b?T*(a-b):-S*(b-a)) + (c>d?T*(c-d):-S*(d-c));
		res += new_effect - old_effect;
		cout << res << "\n";
	}

	return 0;
}

• Subtask 1: 0 / 30
• Subtask 2: 0 / 10
• Subtask 3: 0 / 60