이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int c=502;
vector<int> pl;
long long ans=0, kom[c], elott[c], utan[c], ert, maxi, maxj, am, tav[c][c];
long long dist(int a, int b) {
return pl[a]+pl[b]+abs(kom[b]-kom[a]);
}
long long find_shortcut(int n, vector<int> sz, vector<int> s, int d) {
for (int i=0; i<n-1; i++) kom[i+1]=kom[i]+sz[i];
for (int i=0; i<n; i++) pl.push_back(s[i]);
for (int i=0; i<n; i++) for (int j=0; j<n; j++) {
tav[i][j]=dist(i, j);
if (i!=j) ans=max(ans, tav[i][j]);
}
for (int i=1; i<n; i++) {
elott[i]=elott[i-1];
for (int j=0; j<i-1; j++) elott[i]=max(elott[i], tav[i-1][j]);
}
for (int i=n-2; i>=0; i--) {
utan[i]=utan[i+1];
for (int j=i+2; j<n; j++) utan[i]=max(utan[i], tav[i+1][j]);
}
for (int i=0; i<n; i++) for (int j=i+1; j<n; j++) {
ert=max(elott[i], utan[j]), maxi=0, maxj=0;
for (int k=0; k<i; k++) maxi=max(maxi, tav[k][i]-pl[i]);
for (int k=j+1; k<n; k++) maxj=max(maxj, tav[k][j]-pl[j]);
ert=max(ert, maxi+maxj+d);
for (int k=i; k<=j; k++) {
long long tavi=min(tav[k][i]-pl[i], tav[k][j]-pl[j]+d), tavj=min(tav[k][j]-pl[j], tav[k][i]-pl[i]+d);
ert=max({ert, tavi+maxi, tavj+maxj});
for (int l=k+1; l<=j; l++) {
long long x=min(tav[l][i]-pl[i], tav[l][j]-pl[j]+d);
ert=max(ert, min(x+tavi, tav[k][l]));
}
}
ans=min(ans, ert);
}
return ans;
}
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