# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
291836 | Kastanda | Sails (IOI07_sails) | C++11 | 1092 ms | 2552 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// M
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 100005;
int n, H[N], K[N], C[N];
inline bool Solve(int md)
{
memset(C, 0, sizeof(C));
for (int i = 1; i <= n; i ++)
C[H[i] - K[i] + 1] ++, C[H[i] + 1] --;
for (int i = 1; i < N; i ++)
C[i] += C[i - 1];
ll LeftOver = 0;
for (int i = N - 1; i; i --)
{
int tmp = min(LeftOver, (ll)md - C[i]);
LeftOver -= tmp;
C[i] += tmp;
assert(C[i] <= md);
}
return !LeftOver;
}
int main()
{
scanf("%d", &n);
for (int i = 1; i <= n; i ++)
scanf("%d%d", &H[i], &K[i]);
int le = 0, ri = N, md;
while (ri - le > 1)
{
md = (le + ri) >> 1;
if (Solve(md))
ri = md;
else
le = md;
}
// How to do it with ri you ask? I don't know either ...
Solve(ri);
int ptr = 1;
for (int i = N - 1; i; i --)
if (C[i] == ri)
{
while (ptr < i && C[ptr] == ri)
ptr ++;
if (ptr >= i)
break;
C[i] --;
C[ptr] ++;
}
vector < int > A;
for (int i = 1; i < N; i ++)
{
vector < int > Tbo = {C[i]};
while (Tbo.size())
{
if (!A.size() || A.back() >= Tbo.back())
{
A.push_back(Tbo.back());
Tbo.pop_back();
continue;
}
int nd = (Tbo.back() - A.back() + 1) / 2;
Tbo.back() -= nd;
Tbo.push_back(A.back() + nd);
A.pop_back();
}
}
assert((int)A.size() == N - 1);
for (int i = 1; i < N; i ++)
C[i] = A[i - 1];
for (int i = 1; i < N; i ++)
assert(C[i] <= ri);
bool Fail = 1;
for (int i = 1; i < N; i ++)
if (C[i] == ri)
Fail = 0;
for (int i = 2; i < N; i ++)
assert(C[i - 1] >= C[i]);
assert(!Fail);
ll tot = 0;
for (int i = 1; i < N; i ++)
tot += (ll)C[i] * (C[i] - 1) / 2;
printf("%lld\n", tot);
return 0;
}
Compilation message (stderr)
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