이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "wiring.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int maxn = 1e5 + 10;
int n, m;
pair<ll,ll> p[2*maxn];
ll dp[2*maxn], opt[2*maxn];
ll par[2*maxn], pre[2*maxn];
ll Cost(ll l, ll r){
ll idx = pre[r];
assert(idx >= l);
assert(pre[idx] < l);
ll C1 = p[idx].first*(idx-l+1) - (par[idx]-par[l-1]);
ll C2 = (par[r]-par[idx]) - p[idx+1].first*(r-idx);
return C1 + C2 + (p[idx+1].first-p[idx].first)*max(r-idx,idx-l+1);
}
void calc(int l, int r, int lo, int hi){
if (l >= r)
return;
int m = (l+r) >> 1;
for (int i = lo; i < hi; i++){
ll now = min(dp[i],dp[i-1]) + Cost(i,m);
if (now < dp[m])
dp[m] = now, opt[m] = i;
}
calc(l, m, opt[m], hi);
calc(m+1, r, lo, opt[m]+1);
}
ll min_total_length(vector<int> Red, vector<int> Blue){
n = Red.size(), m = Blue.size();
p[0] = {0, -1};
for (int i = 1; i <= n; i++)
p[i] = {Red[i-1],0};
for (int i = 1; i <= m; i++)
p[i+n] = {Blue[i-1],1};
int tot = n+m;
sort(p+1,p+tot+1);
for (int i = 1; i <= tot; i++){
if (p[i].second == p[i-1].second)
pre[i] = pre[i-1];
else
pre[i] = i-1;
par[i] = par[i-1] + p[i].first;
}
memset(dp, 63, sizeof dp);
dp[0] = 0;
for (int i = 1; i <= tot; i++){
if (pre[i] == 0)
continue;
if (i == tot or p[i].second != p[i+1].second)
calc(pre[i]+1, i+1, pre[pre[i]]+1, pre[i]+1);
}
return dp[tot];
}
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