이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "wiring.h"
#include <bits/stdc++.h>
#define F first
#define S second
#define pb push_back
#define all(x) x.begin(), x.end()
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
const int N = 2e5 + 10;
const ll Inf = 1e18;
ll sm[N], ps[N];
vector<pii> V;
ll dp[N];
ll min_total_length(vector<int> r, vector<int> b) {
for(int i = 0; i < (int) r.size(); i++)
V.pb({r[i], 0});
for(int i = 0; i < (int) b.size(); i++)
V.pb({b[i], 1});
V.pb({-1, -1});
sort(all(V));
int n = ((int) V.size()) - 1;
sm[1] = 1;
for(int i = 2; i <= n; i++)
sm[i] = (V[i].S == V[i - 1].S ? sm[i - 1] : i);
ps[1] = 0;
for(int i = 2; i <= n + 1; i++) ps[i] = ps[i - 1] + V[i - 1].F;
int la, la2;
dp[0] = 0;
for(int i = 1; i <= n; i++){
dp[i] = Inf;
if(sm[i] == 1)
continue;
la = sm[i];
la2 = sm[la - 1];
ll sum = ps[i + 1] - ps[la];
ll dif;
for(int j = la2; j < la; j++){
dif = (i - la + 1) - (la - j);
dp[i] = min(dp[i], min(dp[j], dp[j - 1]) + sum - (ps[la] - ps[j]) + ( dif < 0 ? abs(dif) * V[la].F : abs(dif) * (-V[la - 1].F) ));
}
}
return dp[n];
}
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